Answer:
ΔS = +541.3Jmol⁻¹K⁻¹
Explanation:
Given parameters:
Standard Entropy of Fe₂O₃ = 90Jmol⁻¹K⁻¹
Standard Entropy of C = 5.7Jmol⁻¹K⁻¹
Standard Entropy of Fe = 27.2Jmol⁻¹K⁻¹
Standard Entropy of CO = 198Jmol⁻¹K⁻¹
To find the entropy change of the reaction, we first write a balanced reaction equation:
Fe₂O₃ + 3C → 2Fe + 3CO
To calculate the entropy change of the reaction we simply use the equation below:
ΔS = ∑S
- ∑S
Therefore:
ΔS = [(2x27.2) + (3x198)] - [(90) + (3x5.7)] = 648.4 - 107.1
ΔS = +541.3Jmol⁻¹K⁻¹
M=mol/liter
We know that we have 150ml=.15 L and .1 mol of HCl
Rearranging the molarity equation, we get
mol=M*l
mol=(.15)(.1)
=.015 mol
From the information provided in the question, we can see that; the electron moved up to an energy level and has an energy of 21.72 x 10-19 J.
Bohr's model of the atom tells us that electrons are found in certain specific energy levels. Energy is absorbed when an electron moves from a lower to a higher energy level and energy is released when an electron moves from a higher to a lower energy level.
Given that;
ΔE = E2 - E1
E2 = final energy level
E1 = initial energy level
E2 = ?
E1 = 16.32 x 10-19 J
ΔE = 5.4 x 10-19
E2 = ΔE + E1
E2 = 5.4 x 10-19 + 16.32 x 10-19 J
E2 = 21.72 x 10-19 J
Learn more: brainly.com/question/4612545
Answer:
9
Explanation:
let f(x)= x-7 be equation i
let g(x)= x^2 be equation ii
Substitute x-7 as x in equation 2
implies gf(x) = (x-7)^2=(x-7)(x-7)
substitute x=4 implies
gf(x) = (4-7)(4-7)=(-3)(-3)=9
