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Lisa [10]
3 years ago
7

Trisha and her lab partner filled a beaker with 150 milliliters of a 0.10 M HCl solution. How many moles of HCl are in the beake

r? Remember, molarity = moles liter .
Chemistry
2 answers:
Hatshy [7]3 years ago
8 0

Answer:

Moles of HCl is 0.015.

Explanation:

Molarity of HCl = 0.10 M

Volume of HCl = 150 mL

Conversion factor for mL to L is,

1\ mL = 10^{-3}\ L

So, 150 mL = 0.15 L

Molarity is given by,

Molarity=\frac{Moles}{Volume\ in\ L} \\Moles = Molarity \times Volume\ in\ L

Substitute values in the above formula

Moles = 0.10 \times 0.15\\=0.015\ mol

Moles of HCl is 0.015.

oksian1 [2.3K]3 years ago
7 0
M=mol/liter
We know that we have 150ml=.15 L and .1 mol of HCl
Rearranging the molarity equation, we get
mol=M*l
mol=(.15)(.1)
=.015 mol
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Answer:

1 tablet

Explanation:

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Put everything in one unit, 0.3 g = 300 mg.

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4 0
2 years ago
What mass of HBO2 is produced from the<br> combustion of 139.5 g of B2H6?<br> Answer in units of g.
aliina [53]

Answer:

m_{HBO_2}=441.8gHBO_2

Explanation:

Hello there!

In this case, since the combustion of B2H6 is:

B_2H_6+3O_2\rightarrow 2HBO_2+2H_2O

Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:

m_{HBO_2}=139.5gB_2H_6*\frac{1molB_2H_6}{27.67gB_2H_6} *\frac{2molHBO_2}{1molB_2H_6} *\frac{43.82gHBO_2}{1molHBO_2}

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5 0
2 years ago
The pattern of colors given off by a particular atom is called
babymother [125]

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Explanation:

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3 years ago
CS2 (s) + 3 O2 (g) → CO2 (g) + 2 SO2 (g)
Natasha_Volkova [10]

Answer:

2.067 L ≅ 2.07 L.

Explanation:

  • The balanced equation for the mentioned reaction is:

<em>CS₂(g) + 3O₂(g) → CO₂(g) + 2SO₂(g),</em>

It is clear that 1.0 mole of CS₂ react with 3.0 mole of O₂ to produce 1.0 mole of CO₂ and 2.0 moles of SO₂.

  • At STP, 3.6 L of H₂ reacts with (?? L) of oxygen gas:

It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.

<u><em>using cross multiplication:</em></u>

1.0 mol of O₂ represents → 22.4 L.

??? mol of O₂ represents → 3.1 L.

∴ 3.1 L of O₂ represents = (1.0 mol)(3.1 L)/(22.4 L) = 0.1384 mol.

  • To find the no. of moles of SO₂ produced from 3.1 liters (0.1384 mol) of hydrogen:

<u><em>Using cross multiplication:</em></u>

3.0 mol of O₂ produce → 2.0 mol of SO₂, from stichiometry.

0.1384 mol of O₂ produce → ??? mol of SO₂.

∴ The no. of moles of SO₂ = (2.0 mol)(0.1384 mol)/(3.0 mol) = 0.09227 mol.

  • Again, using cross multiplication:

1.0 mol of SO₂ represents → 22.4 L, at STP.

0.09227 mol of SO₂ represents → ??? L.

∴ The no. of liters of SO₂ will be produced = (0.09227 mol)(22.4 L)/(1.0 mol) = 2.067 L ≅ 2.07 L.

8 0
3 years ago
Adding more baking soda and vinegar to the bag in the Air Bag Lab resulted in faster production of gaseous products True False
nika2105 [10]

Answer:

True

Explanation:

The more of each substanse that you add to the bag will cause it to produce faster and more gas.

5 0
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