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grin007 [14]
3 years ago
14

PLZ SOMEONE HELP THANKS:)))) materials and conclude which is best to use. Full explanation

Chemistry
1 answer:
grin007 [14]3 years ago
3 0

Answer:

For quick facts use reference materials such as encyclopedias, almanacs, or dictionaries. For credible and reputable information, use online databases of academic journals, or peer-reviewed journal articles that are written by scholars and researchers for a specific discipline.

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50/5.2 that’s the equation that you have to solve then whatever comes out yo calculator is the answer
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Describe the chemical reaction based on the
BabaBlast [244]

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Ammonia gas reacts with oxygen gas.

Nitric oxide gas and liquid water are produced.

Platinum is used as a catalyst.

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Explanation:

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How is copper sulphate different to copper sulphide in terms of the elments it contains
son4ous [18]

Answer:

An Element is a substance made up of only one type of atom as like gold, copper, oxygen, etc.

Copper sulphate with molecular formula (CuSO_4), the elements are copper, sulphur and oxygen. It is formed by combination of Cu^{2+} cation and SO_4^{2-} anion.

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6 0
3 years ago
if the lightbulb receives 100 J of electrical energy, and gives off 75 energy, how much heat (thermal energy away from the light
oksano4ka [1.4K]

Answer:

Amount of heat energy released by light bulb = 25 joules

Explanation:

Given:

Energy receive by light bulb = 100 Joules

Energy released by light bulb as light energy = 75 Joules

Find:

Amount of heat energy released by light bulb

Computation:

We know that, energy is neither be created nor destroys

So,

Using Law of conservation of energy

Energy receive by light bulb = Energy released by light bulb as light energy + Amount of heat energy released by light bulb

100 = 75 + Amount of heat energy released by light bulb

Amount of heat energy released by light bulb = 100 - 75

Amount of heat energy released by light bulb = 25 joules

8 0
3 years ago
Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these are decomposed, the sulfur dioxide produce
Diano4ka-milaya [45]
To determine the mass of oxygen per gram of sulfur for sulfur dioxide, we simply obtain the ratio of the mass of oxygen and the mass of sulfur produced from the decomposition of sulfur dioxide. All other values given in the problem statement above are just to confuse us that the question is a difficult one. We do as follows:

mass of oxygen per gram sulfur = 3.45 g / 3.46 g
mass of oxygen per gram sulfur = 0.9971 g O2 / g S
4 0
3 years ago
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