Answer:
HCl < CH₃COOH < NH₃ < NaOH
Explanation:
Given compounds:
Acetic acid: CH₃COOH
Ammonia; NH₃
Hydrochloric acid: HCl
Sodium hydroxide: NaOH
All the solutions are of the same molarity which is 0.1M. We need to see how these compounds dissociate to form solutions in order to establish their pH value:
For Acetic acid;
CH₃COOH + H₂O ⇄ H₃O⁺ + CH₃COO⁻
Acetic acid is a weak acid and it ionizes slightly in solutions. It would have a pH close to 7
For Ammonia;
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
Ammonia is a weak base and it ionizes slightly in solutions. It sets up an equilibrium in the process. It's would be slightly above 7
For HCl:
HCl + H₂O → H₃O⁺ + Cl⁻
HCl is a strong acid and ionizes completely in solutions. It has a very low pH
For NaOH:
NaOH → Na⁺ + OH⁻
NaOH ionizes also completely in solutions and it breaks down into sodium and hydroxide ions. It is a strong base and it would have a high PH value.
HCl < CH₃COOH < NH₃ < NaOH
This is the trend of increasing pH
Explanation:
Answer is
B , The grapes will burst
Answer:
C) cation, loses, anion, gains
Explanation:
Lithium is a metal from Group 1, so it has 1 valence electron. Thus, it loses 1 electron to complete its octet and form the cation Li⁺.
Oxygen is a nonmetal from Group 16, so it has 6 valence electrons. Thus, it gains 2 electrons to complete its octet and form the anion O²⁻.
In the reaction between Li and O, there is a transfer of electrons making an ionic bond. In the bond, lithium would be a cation because it loses an electron, and oxygen would be an anion because it gains 2 electrons.
The answer to your question:
-71,488 J
