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ELEN [110]
2 years ago
11

Ms. Zimmer pushes a trash can and it moves across the cafeteria floor

Mathematics
1 answer:
worty [1.4K]2 years ago
6 0

Answer:

Step-by-step explanation:

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What is extended form for 76.429
Zanzabum
(70x10)+(6x1)+(4x1/10)+(2x1/100)+(9x1/1000)
3 0
3 years ago
HELP PLEASE Connie can buy 48 roses for $120. Which is the cost per rose? A $1.20 B $2.50 © $3.00 D $4.00​
zubka84 [21]

Answer:

B: $2.50

Step-by-step explanation:

$120 ÷ 48 roses = cost per rose ($2.50)

4 0
3 years ago
Solve this system of linear equation the x- and y-value with a comma. 18x+13y=60 6x+2y=6
OLEGan [10]

Answer:

18x + 13y = 60

6x + 2y = 6 ---> 6x = -2y +6 ---> 18x = -6y+18

Substitution

(-6y +18)+13y =60

       -18           -18

--------------------------

7y = 42 so y=6

Then, 6x + 2(6) =6, which you will get x = -1

(-1, 6)

8 0
2 years ago
Read 2 more answers
Valerie has a circular garden. The radius of the garden is 4 feet. She wants to buy edging to outline her circular garden.Which
ss7ja [257]
You'd need to find the distance AROUND the garden, which is also PERIMETER.

To find the perimeter of a circle, you use the following equation: 
2 \pi r 

2 \pi (4) = 8 \pi

8 \pi = 25.13 ft 

I don't know what your answer options are, but chose the option closest to 25.13 ft
4 0
3 years ago
Using the bijection rule to count binary strings with even parity.
AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string <em>a</em> in B9, we define the element f(a) in E10 this way:

  • f(a) = a c {1} if a has an odd number of 1's
  • f(a) = a c {0} if a has an even number of 1's

Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

  • If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = y
  • If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

3 0
3 years ago
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