Answer:
31793 cm^3
Step-by-step explanation:
Equation
Volume = * r^2 * h
Givens
d = 2*r
d = 30
r = 15
h = 45
= 3.14
Solution
V = 3.14 * 15^2 * 45
V = 31793 rounded.
Given that ∠XQR = 180° and ∠LQM = 180°, which equation could be used to solve problems involving the relationships between ∠MQR
and ∠LQR?
A) (3a + 50) + 180 = (140 − 4a)
B) (3a + 50) + (140 − 4a) = 180
C) (140 − 4a) − 180 = (3a + 50)
D) (3a + 50) − (140 − 4a) = 180
A) (3a + 50) + 180 = (140 − 4a)
B) (3a + 50) + (140 − 4a) = 180
C) (140 − 4a) − 180 = (3a + 50)
D) (3a + 50) − (140 − 4a) = 180
2 answers:
Answer:
The answer is B
Step-by-step explanation:
In order to determine the equation, we have to know some properties about the addition of angles.
As the angles ∠XQR and ∠ LQM are 180°, they form straight lines. When two straight lines intercept each other, the angles opposite each other are equal.
The property is called "Vertically Opposite Angles".
Also, we know that ∠ LQM=180°, so it is the same that:
Therefore, the relationship between ∠MQR and ∠LQR is:
C.
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<h2>Answer:</h2>
BC ≅ 11cm
<h2>Step-by-step explanation:</h2>To accomplish this task, follow these steps:
i. Using your ruler, draw a line AB with length 8cm as shown in Figure 1. This will give AB = 8cm
ii. Remove the ruler and place your protractor at the point A and parallel to line AB as shown in Figure 2. Make a dot at the mark 90° of the protractor (See Figure 2). For accuracy, ensure that the 180° mark of the protractor is on the line AB.
iii. From point A through the dot in (ii) above, use a ruler to draw a line AC of length 8cm as shown in Figure 3. This will give AC = 8cm and will also give angle CAB = 90°
iv. Now join points C and B by drawing a line from point A to C using a ruler as shown in Figure 4.
v. Lastly, measure the length of BC by placing your ruler on line BC as shown in Figure 5. This should give a value of about 11cm.
Therefore the length of BC = 11cm approximately.
<em>NB: All figures are attached to this response. </em>
Step-by-step explanation:
We have to find the point in the feasible region which maximizes the objective function. To find that point first we need to graph the given inequalities to find the feasible region.
Steps to graph 3x + y ≤ 12:
First we graph 3x + y = 12 then shade the graph for ≤.
plug any value of x say x=0 and x=2 into 3x + y = 12 to find points.
plug x=0
3x + y = 12
3(0) + y = 12
0 + y = 12
y = 12
Hence first point is (0,12)
Similarly plugging x=2 will give y=6
Hence second point is (2,6)
Now graph both points and joint them by a straight line.
test for shading.
plug any test point which is not on the graph of line like (0,0) into original inequality 3x + y ≤ 12:
3(0) + (0) ≤ 12
0 + 0 ≤ 12
0 ≤ 12
Which is true so shading will be in the direction of test point (0,0)
We can repeat same procedure to graph other inequalities.
From graph we see that ABCD is feasible region whose corner points will result into maximum or minimu for objective function.
Since objective function is not given in the question so i will explain the process.
To find the maximum value of objective function we plug each corner point of feasible region into objective function. Whichever point gives maximum value will be the answer
The sum of y and g is
5 less than this is