Given that ∠XQR = 180° and ∠LQM = 180°, which equation could be used to solve problems involving the relationships between ∠MQR
and ∠LQR?
A) (3a + 50) + 180 = (140 − 4a)
B) (3a + 50) + (140 − 4a) = 180
C) (140 − 4a) − 180 = (3a + 50)
D) (3a + 50) − (140 − 4a) = 180
A) (3a + 50) + 180 = (140 − 4a)
B) (3a + 50) + (140 − 4a) = 180
C) (140 − 4a) − 180 = (3a + 50)
D) (3a + 50) − (140 − 4a) = 180
2 answers:
Answer:
The answer is B
Step-by-step explanation:
In order to determine the equation, we have to know some properties about the addition of angles.
As the angles ∠XQR and ∠ LQM are 180°, they form straight lines. When two straight lines intercept each other, the angles opposite each other are equal.
The property is called "Vertically Opposite Angles".
Also, we know that ∠ LQM=180°, so it is the same that:
Therefore, the relationship between ∠MQR and ∠LQR is:
C.
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Answer:
H
Step-by-step explanation:
Out of all of the answers provided, H seems like the equation that makes the most sense.
Make sure you divide 300 sticks by 60 sticks (box max) to get the number of boxes.
So, Mr. Hanson would need to have 5 more boxes in order to get the total amount of 480 sticks.
From that, H would be considered the best equation that Mr. Hanson would use.