Given that ∠XQR = 180° and ∠LQM = 180°, which equation could be used to solve problems involving the relationships between ∠MQR
and ∠LQR?
A) (3a + 50) + 180 = (140 − 4a)
B) (3a + 50) + (140 − 4a) = 180
C) (140 − 4a) − 180 = (3a + 50)
D) (3a + 50) − (140 − 4a) = 180
A) (3a + 50) + 180 = (140 − 4a)
B) (3a + 50) + (140 − 4a) = 180
C) (140 − 4a) − 180 = (3a + 50)
D) (3a + 50) − (140 − 4a) = 180
2 answers:
Answer:
The answer is B
Step-by-step explanation:
In order to determine the equation, we have to know some properties about the addition of angles.
As the angles ∠XQR and ∠ LQM are 180°, they form straight lines. When two straight lines intercept each other, the angles opposite each other are equal.
The property is called "Vertically Opposite Angles".
Also, we know that ∠ LQM=180°, so it is the same that:
Therefore, the relationship between ∠MQR and ∠LQR is:
C.
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Answer:
Mid point of the given end points =
Step-by-step explanation:
Given the end points of the line segment are :
(0, ) & (
,0)
We will use the mid point formula when two points are: (x₁,y₁) & (x₂,y₂)
mid point =
now put the value of x₁ = 0
x₂ =
y₁ =
y₂ = 0
mid point =
=
That's the final answer.