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adoni [48]
3 years ago
15

Your visually impaired friend asked you to enlarge your notes from class so he can study. You took notes on 8.5-inch by 11-inch

paper. The enlarged copy has a smaller side with a length of 10 inches. What is the scale factor of this dilation?
Find the scale factor.
Mathematics
1 answer:
Tema [17]3 years ago
8 0

Answer:FINDING A SCALE FACTOR Your visually impaired friend asked you to enlarge your notes from class so be can study. You took notes on 8.5-inch by 11-inch.

Step-by-step explanation:thank you

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What is the missing angle<br> measure?
algol [13]

Answer:

x = 136º

Step-by-step explanation:

x = 180 - (29 + 15)

x = 180 - 44

x = 136

<em>Hope that helps! :)</em>

<em></em>

<em>-Aphrodite</em>

3 0
3 years ago
Assume that it costs Apple approximately E(x) 25,600 + 100x + 0.012 dollars to manufacture x 32GB iPods in a day. (a) The averag
uranmaximum [27]

Answer:

(a)C'(x)=\dfrac{x^2-2560000}{x^2}

(b)x=1600, Minimum Average Cost Per iPod=$132

(c)C''(x)=\dfrac{5120000}{x^3}

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

Step-by-step explanation:

Given that it costs Apple approximately $ C(x) to manufacture x 32GB iPods in a day, where:

C(x)=25,600+100x+0.01x^2

(a)The average cost per iPod when they manufacture x iPods in a day is given by:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}

The average cost per iPod is therefore:

C'(x)=\dfrac{x^2-2560000}{x^2}

(b)To minimize average cost of x iPods per day, we set the average cost per iPod=0 and solve for x.

C'(x)=\dfrac{x^2-2560000}{x^2}=0\\x^2-2560000=0\\x^2=2560000\\x=\sqrt{2560000}=1600

The resulting minimum average cost (at x=1600) is given as:

Cost \:Per \:iPod=\dfrac{C(x)}{x} =\dfrac{25,600+100x+0.01x^2}{x}\\\dfrac{25,600+100(1600)+0.01(1600)^2}{1600}\\=\$132

<u>Second derivative test</u>

(c)The answer above is a critical point for the average cost function. To show it is a minimum, we calculate the second derivative of the average cost function.

C''(x)=\dfrac{5120000}{x^3}

At the critical point,  x=1600

C''(1600)=\dfrac{5120000}{1600^3}=0.00125

The result, C''(1600) is positive, which means that the average cost is Concave up at the critical point, and the critical point is a minimum.

3 0
3 years ago
What is the area of this figure?
kenny6666 [7]

Answer:

161

Step-by-step explanation:

8*14+13*3+(5*4)/2

112+39+10 = 161

4 0
3 years ago
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Which of the following statements provides the correct freezing and boiling points of water on the Celsius and Fahrenheit temper
dalvyx [7]

Answer: i need a pic

Step-by-step explanation:

6 0
3 years ago
Q and R are not mutually exclusive events. If P(Q)=5/8 and P(R)=1/8 and P(Q and R)=1/32,Find P(q or R)
artcher [175]
The solution for this problem is just adding and subtracting fractions. We all know how to add and subtract function because our teacher since high school teach us how to. P(Q or R) = P(Q) + P(R) - P(Q and R) = 5/8 + 1/8 - 1/32 = 23/32

The answer to this question is 23/32.
8 0
4 years ago
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