Solve the system of equations using the linear combination method {5p-3q=-39 -2p-3q=3

Mathematics

2 answers:

VikaD [51]2 years ago

6 0

Answer:

p=-6

q=3

Step-by-step explanation:

5p-3q=-39

-2p-3q=3

Multiply the second equation by -1

2p +3q = -3

Add the first equation and the modified second equation

5p-3q=-39

2p +3q = -3

---------------------

7p = -42

Divide by 7

7p/7 = -42/7

p = -6

Now we can find q

2p +3q = -3

2(-6) +3q = -3

-12 +3q = -3

Add 12 to each side

-12+12 +3q = -3+12

3q = 9

Divide by 3

3q/3 = 9/3

q=3

spayn [35]2 years ago

4 0

Answer:

p=-6

q=3

Step-by-step explanation:

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What is the question of the line that passes through the point (-2,-2) and has a slope of 4. Plz someone answer

Studentka2010 [4]

Answer:y=4x+6

Step-by-step explanation:

We have the information that the slope is 4 and the line goes through the point (-2,-2). With this information, we can make a linear equation in a point slope form ( $y - y_{1}= m * (x - x_{1})$ , so the equation would be $y+2=4(x+2)$ , or simplified, $y+2=4x+8.$ in order to solve for y (to make it a slope-intercept equation), we must subtract 2 from both sides. This gives us the equation y=4x+6. Hope this helps!