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postnew [5]
3 years ago
9

A movie theater charges 15 for standard viewing , 20 for 3D viewing , and $35 for Dinner and a Movie viewing . There are four ti

mes as many 3D viewing seats as Dinner and a Movie seats. If the theater brings in $53,000 when tickets to all 3000 seats are sold, determine the quantity of each type of seat in the movie theater.
Mathematics
1 answer:
trapecia [35]3 years ago
4 0

Answer:

cmsabcacsacsavsac

Step-by-step explanation:

cacacac,jbb

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A room has dimensions of 12' by 13' by 8'. Calculate the amount of molding necessary for a decorative strip at the floor and at
faust18 [17]
The dimensions of a room are determined by its length, width and height.  In this problem we will assign a length of 12', a width of 13', and a height of 8' (as standard ceiling heights in most homes are 8' high).  To calculate the amount of molding needed for strips at the top of the room and the bottom of the room we need to find the perimeter of the room.  A length of 12' and a width of 13' make this room a rectangle.  Determine the perimeter by adding 12' + 13' and multiplying the sum by 2 to get 50'.  Multiply 50' x 2 to account for a decorative strip of molding at the floor and the ceiling and you get 100' total molding needed.
7 0
4 years ago
How do I get the answer for 1 1/2 x 3 x 1 1/9
Mekhanik [1.2K]

\boxed{1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}=5}

<h2>Explanation:</h2>

in this problem we have the following expression:

1 \frac{1}{2}\times 3 \times 1 \frac{1}{9}

So here:

1 \frac{1}{2} \ and \ 1 \frac{1}{9} \ are \ written \ as \ mixed \ fractions

Let's convert them as improper fractions:

1 \frac{1}{2}=1+\frac{1}{2}=\frac{1\times 2+1}{2}=\frac{3}{2} \\ \\ 1 \frac{1}{9}=1+\frac{1}{9}=\frac{1\times9 +1}{9}=\frac{10}{9}

Rewriting our expression:

\frac{3}{2}\times 3 \times \frac{10}{9}=\frac{3\times 3 \times 10}{2\times 9}=\frac{90}{18}=5

<h2>Learn more:</h2>

Simplify: brainly.com/question/10644722

#LearnWithBrainly

3 0
3 years ago
Hello can anyone help me ? here the question
lesantik [10]

Answer:

A. 1/5k - 2/3j and -2/3j +1/5k

Step-by-step explanation:

A. 1/5k - 2/3j and -2/3j +1/5k

B. 1/5k - 2/3j and -1/5k +2/3j

There is a change in the signs of each term

1/5k changed to -1/5k

-2/3j changed to +2/3j

Not equivalent

C. 1/5k - 2/3j and 1/5j - 2/3k

There is a change in the variables

1/5k changed to 1/5j

-2/3j changed to -2/3k

D. 1/5k - 2/3j and 2/3j - 1/5k

The is a change in the signs of each term

1/5k changed to -1/5k

-2/3j changed to +2/3j

The only equivalent expression is

A. 1/5k - 2/3j and -2/3j +1/5k

3 0
3 years ago
The average score of all golfers for a particular course has a mean of 75 and a standard deviation of 4. Suppose 64 golfers play
Vilka [71]

Answer:

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 75, \sigma = 4, n = 64, s = \frac{4}{\sqrt{64}} = 0.5

Find the probability that the average score of the 64 golfers exceeded 76.

This is 1 subtracted by the pvalue of Z when X = 64.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{76 - 75}{0.5}

Z = 2

Z = 2 has a pvalue of 0.9772

1 - 0.9772 = 0.0228

0.0228 = 2.28% probability that the average score of the 64 golfers exceeded 76.

6 0
3 years ago
In 3-8, find the missing side length of each right triangle. 50yd.<br> 30yd.
denis23 [38]
Hi! so you didn’t let us know which side length is missing and it kind of matters so i’ll attach an image so you can just copy the one that looks most like yours.

7 0
3 years ago
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