Answer:
The answer to this question is given below in this explanation section.
Explanation:
A free WiFi connection in a public space can seem like a lifesaver when you are on the go.But if you decide to use public WiFi just be aware that you could be making yourself an easy target for hackers and putting your information and more at risk.
one of the dangers of using a public WiFi network is that data over this type of open connection is often encrypted and unsecured ,leaving you vulnerable to a man in the middle attack.It when a cyber criminal exploits a security flaw in the network to intercept data
- Avoid connecting to public WiFi connection. i if you must use a public WiFi hotpots also use a virtual privater network to secure your connection.
- Do not log in to password protected websites that contains sensitive information when using a public WiFi connection for example banking and social networking sites or even email.
- Keep your software patched and up to date and all your devices even your mobiles ones to avoid any potential infection by viruses or malware if you do use unsecured public WiFi.
Answer:
Yes, both of these segments (A and B) will be directed to the same socket at Host C .
Explanation:
Suppose both Host A and Host B each send a UDP segment to Host C with destination port number 6789, surely , both of these segments will be directed to the same socket at Host C .
Reason being that, the operating system will provide the process with the IP details to distinguish between the individual segments arriving at host C- for each of the segments (A and B) recieved at Host C.
Answer:
bluetooth
Explanation:
cause u need to ask Google
Get a screen recorder then record all the videos u wanna save then u can go back and watch them wenever u want to
Answer:
#include <iostream>
using namespace std;
int main() {
int a[4][5];//declaring a matrix of 4 rows and 5 columns.
for(int i=0;i<4;i++)
{
for(int j=0;j<5;j++)
{
if(i==3)//initializing last row as 0.
{
a[i][j]=0;
}
else//initializing last row as 1.
{
a[i][j]=1;
}
}
}
for(int i=0;i<4;i++)
{
for(int j=0;j<5;j++)
cout<<a[i][j]<<" ";//printing the matrix.
cout<<endl;
}
return 0;
}
Output:-
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
0 0 0 0 0
Explanation:
I have created a matrix of size 4 rows and 5 columns.I have used for loops to fill the array.To fill the last row with 0 i have used if statement.else we are filling it with 1.
