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hichkok12 [17]
3 years ago
5

If your computer is running slowly, which of the following is most likely to solve the problem?

Computers and Technology
2 answers:
Rufina [12.5K]3 years ago
5 0
One of the easiest fixes is going to be running a scan of it.  It could be malware, or even a virus slowing it down.  If nothing comes up, cleaning it out with a can of air is the next best solution.  Dust is very bad for a computer and it can cause it to overheat and/or slow down.  While you are cleaning it out, go ahead and make sure all the cords are plugged in.  However, if your computer runs slowly, but it works, it probably isn't the cords.  That's what I would do.  
svp [43]3 years ago
4 0
Your answer would be A. Scanning, cleaning, and optimizing your hard drive.

If this answer is incorrect, then i am sorry.
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The owner of a candle shop has asked for your help. The shop sells three types of candles as shown below:
Bezzdna [24]

Answer:

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

  double cost = 0;

  double priceF, priceS, priceT;

  int nOne = 0, nTwo = 0, nThree = 0;

  int fBurn, sBurn, tBurn;

  int burnTime = 0;

  isEnd = "n";

   while (isEnd == "n"){

      Scanner in = new Scanner(System.in);

      int option = in.nextInt();

      if (option == 1){

            priceF = 2.50;

            fBurn = 5;

            System.out.print("Enter number of items: ");

            nOne += in.nextInt();

            burnTime += fBurn * nOne;

            cost += priceF * nOne;

        } else if (option== 2){

            priceS = 3.75;

            sBurn = 7;

            System.out.print("Enter number of items: ");

            nTwo += in.nextInt();

            burnTime += sBurn * nTwo;

            cost += priceS * nTwo;

        } else if(option == 3){

            priceT = 5.99;

            tBurn = 12;

            System.out.print("Enter number of items: ");

            nThree += in.nextInt();

            burnTime += tBurn * nThree ;

            cost += priceT * nThree;

        } else{

            System.out.println("option must be between 1 and 3");

        }

      System.out.print("Do you want to end the order? y/n: ");

      isEnd = in.nextLine();

  }

  System.out.println("Number of Type 1 candles bought : "+nOne);

  System.out.println("Number of Type 2 candles bought : "+nTwo);

  System.out.println("Number of Type 3 candles bought : "+nThree);

  System.out.println("Total cost is : "+cost);

  System.out.println("Total burn time is : "+burnTime);

  double cpm = (burnTime * 60) / cost;

  System.out.println("Cost per minute : "+cpm);

}

}

Explanation:

The Java program prompts the user to continuously choose from three options 1, 2 and 3. The prices, the burn time and the cost per minute burn of the total candles ordered are printed out.

4 0
3 years ago
Q. Which protocol would best serve to authorize users to access directory services?
Arlecino [84]

Answer:

Lightweight directory access protocol (LDAP)

Explanation:

Lightweight directory access protocol is a protocol that provides a common open protocol for interfacing and querying a directory service information given by a network operating system. LDAP is an application layer protocol that uses port number 389 via tcp and udp. LDAP queries are transmitted in text and allows for all or some data be queried anonymously.

Lightweight directory access protocol, ordinarily does not require user authentication connection, but this can be configured to ask for user credentials.

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Graphics Interchange Format! :)
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Answer:

B. Naruto

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