X^2+12x+6=0 subtract 6 from both sides...
x^2+12x=-6 halve linear coefficient, square it, and add it to both sides...
x^2+12x+36=30 now the left side is a perfect square...
(x+6)^2=30 take square root of both sides...
x+6=30^(1/2) subtract 6 from both sides...
x=-6-30^(1/2) and -6+30^(1/2)
29.99 * 3 =89.97 89.97 with 30% off = 62.98 and 5% of 62.98 =3.15 so 62.98 + 3.15 = 66.13$
180.00 + 14.95 + 8.95 = 203.09 - 15% = 173.44 + 4% = 180.38
5.65 + 5% of 5.65 = 5.93
i think this is all right you might want to check my work!
Area (square)=side²
therefore:
side²=200 feet²
side=√(200 feet²)=14.142 feet≈14.1 feet.
solution: side of square=14.1 feet.
the answer is the presence of a true nucleus
