You have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the num
ber of dimes. Is your friend correct? Let d represent the number of dimes
An equation that models this situation is _____=2.80
(I’m so stupid help)
1 answer:
Answer:
Step-by-step explanation:
d = number of dimes
2.80 = 0.1d + 0.25 (d + 8 )
2.80 = 0.1d + 0.25d + 2 Combine like terms
2.80 = 0.35d + 2 Subtract 2 from both sides
0.80 = 0.35d Divide both sides by 0.35
d ≈ 2.29
No, it's not possible to have more quarters than dimes when the total is $2.80 because it's not possible to have part of a dime.
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Step-by-step explanation:
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Answer:
x = - 27/8

Step-by-step explanation:
¹²⁾x/5 - ¹²⁾1/5 = ²⁰⁾x/3 + ¹⁵⁾1/4
12x - 12 = 20x + 15
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x = - 27/8
