the force between the electron and the proton.
a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
the radial acceleration of the electron.
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
the speed of the electron.
c) Now use a = v² / r
where a was found above
and r was given
<span> the period of the circular motion.</span>
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given
Atp is a form of energy and it is generated through a chemical process called substrate level phosphorylation.
<h3 /><h3>What is substrate level phosphorylation?</h3>
Substrate-level phosphorylation is a reaction that makes use of substrate to generate Adenosine triphosphate (ATP) which is a form of energy.
ATP is produced through the transfer of phosphate group from the substrate directly to adenosine diphosphate (ADP).
Therefore, substrate-level phosphorylation generates the atp produced in glycolysis.
Learn more on substrate level phosphorylation here,
brainly.com/question/7331523
Answer:
strong winds that blow in short spurts over a small distance
Explanation:
Generally, the most common factor that causes the largest waves in the ocean is winds. this is also called wind-driven waves of the ocean when the surface wind flows on the surface of the ocean, this disturbance creates the friction between surface wind and surface of the ocean which creates waves in the ocean
Answer:
Explanation:
Hello!
In this case, for such calorimetry problem, we can notice that the combustion of the compound releases the heat which causes the increase of the temperature by 11.95 °C, it means that we can write:
In such a way, we can compute the total released heat due to the combustion considering the calorimeter specific heat and the temperature raise:
Next, we compute the molar heat of combustion of the compound by dividing by the moles, considering 1.400 g were combusted:
Thus, we obtain:
Best regards!
Answer:
This is
1 mole = 18 gram = 6×10^23 molecules
1 gram = ?
1 gram= 18/6×10^23 atoms
1 gram =3×10^-23 atoms
