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2 years ago

8

Organisms do not adapt as a result of competition for resources. Please select the best answer from the choices provided T F

2 answers:

Ymorist [56]2 years ago

6 0

The answer is FALSE.
Hope this helps.

zhenek [66]2 years ago

6 0

Organisms do not adapt as a result of competition for resources. Please select the best answer from the choices provided T OR F its FALSE

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_________ energy is to the fission and fusion within an atom as ________ energy is to the fission of atomic compounds.

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I would say C bc I don’t rlly think it’s A or B

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Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

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2 years ago

I need help please WOTH this

barxatty [35]

Answer:

Kenma I'll help you! it's B.

Explanation:

I hope I helped you Kenma

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What is the total number of grams of mg consumed when 0.50 mole of h2 is produced

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Answer:

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Which instrument is used to measure mass?

lara [203]

A triple beam balance is used to measure mass

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