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Xelga [282]
3 years ago
7

Which college classes would a student most likely take to become an oceanographer? Select 4 choices.

Chemistry
1 answer:
Setler [38]3 years ago
5 0

Answer:

marine biology

coastal ecology

astronomy

meteorology

Explanation:

As a college student, to study oceanography one will have to take classes in the field of marine biology, coastal ecology, astronomy and meteorology.

An oceanographer is someone or a professional that studies the ocean in order have more scientific knowledge about them.

Oceanography is a merger of geology, biology, chemistry, physics as it pertains to the ocean.

  • There is no need to study human anatomy to study oceanography.
  • Marine biology and coastal ecology deals with study of life forms in their marine environment.
  • Astronomy and meteorology helps to gain insight about the formation of the ocean and how weather relates to the ocean.
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Explain reaction of metals with the following with the help of chemical equations. i) with acids ii) with oxygen iii) with water
Amiraneli [1.4K]

i. When an acid reacts with metal, a salt and hydrogen are produced:

ii. When oxygen and metal react,  metal oxide forms also known as rust

iii. metal and water produce hydrogen gas

6 0
3 years ago
What is the speed of a wave with a wavelength of 3 m and a frequency of .1 Hz?
ratelena [41]

Answer:

wave velocity= frequency × wave length

=1×3

=3m/s

Explanation:

The distance covered by the wave in one second is equal to its wavelength, therefore,

wave velocity=wavelength/time period

OR wave velocity= frequency× wavelength

You can assume velocity as speed here.

3 0
3 years ago
Calculate the cfse for a d^3 system in an octahedral field in units of ∆_o. In other words, do not enter "∆_o" with your answer.
Rudik [331]

Magnetic moment (spin only) of octahedral complex having CFSE=−0.8Δo and surrounded by weak field ligands can be : Q

To answer this, the Crystal Field Stabilization Energy has to be calculated for a (d3 metal in both configurations. The geometry with the greater stabilization will be the preferred geometry. So for tetrahedral d3, the Crystal Field Stabilization Energy is: CFSE = -0.8 x 4/9 Δo = -0.355 Δo.

[Co(CN)64-] is also an octahedral d7 complex but it contains CN-, a strong field ligand. Its orbital occupancy is (t2g)6(eg)1 and it therefore has one unpaired electron. In this case the CFSE is −(6)(25)ΔO+(1)(35)ΔO+P=−95ΔO+P.

The crystal field stabilization energy (CFSE) (in kJ/mol) for complex, [Ti(H2O)6]3+. According to CFT, the first absorption maximum is obtained at 20,3000cm−1 for the transition.

To learn more about crystal field stabilization energy  visit:brainly.com/question/29389010

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8 0
11 months ago
Group 1A (or IA) of the periodic table are the alkali metals: hydrogen (H), lithium (Li), sodium (Na), potassium (K), rubidium (
ziro4ka [17]

Answer: with a non metallic atom

Explanation:

3 0
3 years ago
Question 1 (4 points)
Vilka [71]
To be honest answer might be a
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