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vredina [299]
4 years ago
5

Find the surface area of the triangular prism. A triangular prism. The base is a right triangle with base 1 foot, height 2 feet

and third side 2 point 2 feet. The height of the prism is 3 feet.
Mathematics
1 answer:
mylen [45]4 years ago
3 0

Answer:

<h2>17.6ft²</h2>

Step-by-step explanation:

The formula for calculating the surface area of a triangular prism is expressed as shown below:

SA= bh + pH

b= base of the triangle

h- height of the triangle

p= perimeter of the triangle

H= height of the prism

Given b = 1foot

h = 2feet

perimeter of the triangle = sum of all its sides = 1ft + 2ft + 2.2ft

p = 5.2ft

H = 3ft

Substituting the values into the formula for finding the surface area:

SA = 1(2)+5.2(3)

SA = 2+15.6

SA = 17.6ft²

The surface area of the triangular prism is  17.6ft²

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THE GRAPH IS BELOW THANKS :) Anika is on the crew to set up rides for the state fair. The crew does most of the setup on the day
Vaselesa [24]

Answer:

(a) We will form an equation of line from the points given (6,10) and (2,15)

Using:y-y_1=\frac{y_2-y_1}{x_2-x_1}\cdot (x-x_1)

On substituting the values in the formula above we will get the required equation of line.

y-10=\frac{15-10}{2-6}\cdot (x-6)

\Rightarrow y-10=\frac{5}{-4}\cdot (x-6)

On simplification we will get:

y=\frac{1}{4}(-5x+70)

(b) We need to tell at day 0 put x=0 in above equation:

y=\frac{1}{4}(-5\cdot 0+70)

y=70

Anika worked for 70 hours on the set up crew on the day the fair arrived at the fairgrounds day 0.

Now, we need to tell decrease per day which is equal to the slope of line

To find the slope compare the equation with general equation which is y=mx+c where m is slope

Here, in y=\frac{1}{4}(-5x+70)

m=\frac{-5}{4}  which is the decrease per day.


3 0
3 years ago
A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet
gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

h(x)=10+0.1(x^{1.5})

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}

s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx

s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx

s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx

Let 1+0.0225x=t

dx=\frac{1}{0.0225}dt

s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt

s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}

s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}

s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)

s=28.21

Weight of cable=28.21\times 10.4=293.38pound

8 0
3 years ago
Easy points i just have a question. Is this picture showing up?
tiny-mole [99]
Yes it does have a great day
6 0
4 years ago
Read 2 more answers
Helppp!!!and thanks.
horsena [70]

Answer:

Step-by-step explanation:

12inches/foot , 12x132=1,584 inches

8 0
3 years ago
Lines AD and BC are parallel.
allochka39001 [22]

*see attachment for the missing figure

Answer:

Angle ADE = 45°

Angle DAE = 30°

Angle DEA = 105°

Step-by-step explanation:

Since lines AD and BC are parallel, therefore:

Given that angle Angle CBE = 45°,

Angle ADE = Angle CBE (alternate interior angles are congruent)

Angle ADE = 45° (Substitution)

Angle DAE = Angle ACB (Alternate Interior Angles are congruent)

Angle ACB = 180 - 150 (angles on a straight line theorem)

Angle ACB = 30°

Since angle DAE = angle ACB, therefore:

Angle DAE = 30°

Angle DEA = 180 - (angle ADE + angle DAE) (Sum of angles in a triangle)

Angle DEA = 180 - (45 + 30) (Substitution)

Angle DEA = 180 - 75

Angle DEA = 105°

8 0
3 years ago
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