Answer:
(a) We will form an equation of line from the points given (6,10) and (2,15)
Using:
On substituting the values in the formula above we will get the required equation of line.
On simplification we will get:
(b) We need to tell at day 0 put x=0 in above equation:
Anika worked for 70 hours on the set up crew on the day the fair arrived at the fairgrounds day 0.
Now, we need to tell decrease per day which is equal to the slope of line
To find the slope compare the equation with general equation which is y=mx+c where m is slope
Here, in
which is the decrease per day.
Answer:
293.38 pounds
Step-by-step explanation:
We are given that
Distance between poles=35 feet
Weight of cable=10.4 per linear foot
We have to find the weight of the cable.
Differentiate w.r.t
Let 
![s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D%5Cfrac%7B2%7D%7B0.0225%7D%5Ctimes%5Cfrac%7B2%7D%7B3%7D%5Bt%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%5D%5E%7B17.5%7D_%7B0%7D)
![s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}](https://tex.z-dn.net/?f=s%3D2%5Ctimes%20%5Cfrac%7B2%7D%7B3%5Ctimes0.0225%7D%5B%281%2B0.0255x%29%5E%7B%5Cfrac%7B3%7D%7B2%7D%5D%5E%7B17.5%7D_%7B0%7D)
s=28.21
Weight of cable=
pound
Yes it does have a great day
Answer:
Step-by-step explanation:
12inches/foot , 12x132=1,584 inches
*see attachment for the missing figure
Answer:
Angle ADE = 45°
Angle DAE = 30°
Angle DEA = 105°
Step-by-step explanation:
Since lines AD and BC are parallel, therefore:
Given that angle Angle CBE = 45°,
Angle ADE = Angle CBE (alternate interior angles are congruent)
Angle ADE = 45° (Substitution)
Angle DAE = Angle ACB (Alternate Interior Angles are congruent)
Angle ACB = 180 - 150 (angles on a straight line theorem)
Angle ACB = 30°
Since angle DAE = angle ACB, therefore:
Angle DAE = 30°
Angle DEA = 180 - (angle ADE + angle DAE) (Sum of angles in a triangle)
Angle DEA = 180 - (45 + 30) (Substitution)
Angle DEA = 180 - 75
Angle DEA = 105°
