A hemispherical container, 26 inches in diameter, is filled with a liquid at 20C and weighed. The liquid weight is found to be 1
1 answer:
Answer:
The answer is below
Explanation:
a) Density is the ratio mass of a substance to the total volume it occupies. The SI unit of density is kg/m³. The formula for density is:
Density = mass / volume
1 ounce = 0.0283495 kg
1 inch = 0.0254 m
The mass of liquid = 1617 ounces =
diameter of container (d) = 26 inches =
Radius = d/2 = 0.66/2 = 0.33 m
The volume of a hemisphere = (2/3)πr³
Volume =
Density = mass / volume = 45.84 kg / 0.075 m³ = 609.04 kg/m³
b) Specific weight = density × acceleration due to gravity = 609.04 kg/m³ × 9.807 m/s² = 5972.83 N/m³
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Answer:
Total wight =640.7927 KN
Explanation:
Given that
do= 61 cm
L =120
t= 0.9 cm
That is why inner diameter of the pipe
di= 61 - 2 x 0.9 cm
di=59.2 cm
Water density ,ρ = 1 kg/L = 1000 kg/m³
Weight of the pipe ,wt = 2500 N/m
wt = 2500 x 120 N = 300,000 N
The wight of the water
wt ' = ρ V g
wt'=340792.47 N
That is why total wight
Total wight = wt + wt'
Total wight =300,000+ 340792.47 N
Total wight =640,792.47 N
Total wight =640.7927 KN
Answer:
C) Dependent on the mass flows in and out.
Explanation:
Lets take control volume(CV)
Take
=inlet mass flow rate
=exit mass flow rate
If we take unsteady flow process then inlet mass can not be equal to exit mass.Some mass can store if inlet mass flow rate is high and exit mass flow rate is low.
So mass of control volume
.
so above we can say that mass of control volume dependent on inlet and exit mass.
Answer:
A. 0.0283 mm3/min
B. 15850.2 gal/min
C. 0.2642 gal/min
D. 1.7 m3/hour
Explanation:
A.
[(1 in)3/min *(25.4mm)3/(1 in)]
= 0.02832 mm3/min
B.
[(1m)3/sec*(264.173gal)/(1m)3]*(60secs)/1min
= 15850.2 gal/min
C.
[(Liter/min)*(0.264172gal/liter)]
=0.2642 gal/min
D.
[(1ft)3/min*(0.3048m)3/(1ft)3*(60mins/1hour)]
=1.7 m3/hour
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