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3 years ago

Create a story with nuclear engineer (not so long and not so short)

Engineering

1 answer:

Zepler [3.9K]3 years ago

5 0

Answer:

I can't write stories well, but I can give character advice!

Explanation:

A really important thing is to make sure your characters act human. In a lot of stories, humans act... well, like aliens or superheroes.
Come up with unique traits and descriptions (ex: 2 different colored eyes, spunky, bright orange hair)
POV really matters! Choosing the wrong POV might make the character seem to flawed, or too perfect, so POV is one of the most important things in a story!
Don't be afraid to make your main character stray from the usual, but make sure there's other characters that stand out, because it gets quite boring if there's only 1 unique character!

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An example of the split-off point in oil, gasoline, and kerosene production is that point where crude oil is

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4 years ago

What is the difference between a series circuit and a parallel circuit?

serg [7]

Answer:

In a parallel circuit, the voltage across each of the components is the same, and the total current is the sum of the currents flowing through each component. ... In a series circuit, every device must function for the circuit to be complete. If one bulb burns out in a series circuit, the entire circuit is broken.

Explanation:

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3 years ago

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jek_recluse [69]

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3 years ago

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A normal shock wave takes place during the flow of air at a Mach number of 1.8. The static pressure and temperature of the air u

Darina [25.2K]

Answer:

The pressure upstream and downstream of a shock wave are related as

$\frac{P_{1}}{P_{o}}=\frac{2\gamma M^{2}-(\gamma -1)}{\gamma +1}$

where,

$\gamma$ = Specific Heat ratio of air

M = Mach number upstream

We know that $\gamma _{air}=1.4$

Applying values we get

$\frac{P_{1}}{100kPa}=\frac{2\times 1.4\times 1.8^{2}-(1.4 -1)}{1.4 +1}\\\\\frac{P_{1}}{100kPa}=3.61\\\\\therefore P_{1}=361.33kPa(Absloute)$

Similarly the temperature downstream is obtained by the relation

$\frac{T_{1}}{T_{o}}=\frac{[2\gamma M^{2}-(\gamma -1)][(\gamma -1)M^{2}+2]}{(\gamma +1)^{2}M^{2}}$

Applying values we get

$\frac{T_{1}}{423}=\frac{[2\times 1.4\times 1.8^{2}-(1.4-1)][(1.4-1)1.8^{2}+2]}{(1.4+1)^{2}\times 1.8^{2}}\\\\\therefore \frac{T_{1}}{423}=1.53\\\\\therefore T_{1}=647.85K=374.85^{o}C$

The Mach number downstream is obtained by the relation

$M_{d}^{2}=\frac{(\gamma -1)M^{2}+2}{2\gamma M^{2}-(\gamma -1)}\\\\\therefore M_{d}^{2}=\frac{(1.40-1)\times 1.8^{2}+2}{2\times1.4\times 1.8^{2}-(1.4-1)}\\\\\therefore M_{d}^{2}=0.38\\\\M_{d}=0.616$

3 0

4 years ago

If you install special sound-reflecting windows that reduce the sound intensity level by 33.0 dBdB , by what factor have you red

Sever21 [200]

Answer:

The sound intensity is reduced by a factor of 1995.26

Explanation:

When comparing two sound intensities, the intensity level is measured in the unit of decibel or dB. The intensity of the threshold of hearing for a human being is 10^−12 W/m^2 . When the intensity level is zero, it means that the sound intensity is the same as the threshold of hearing.

The reduced sound intensity level is given as 33 dB, so

10 log (I/Io) = - 33

I : intensity of the sound

Io ( = 10^−12 W/m^2): threshold of hearing

So, the intensity ratio is

I/Io = 10^-3.3

= 5.01 x 10^-4

1/ 5.01 x 10^-4 = 1995.26

3 0

4 years ago