Create a story with nuclear engineer (not so long and not so short)
1 answer:
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Given:
max displacement, A = 3.2 m
f= 50 Hz
at t = 0, displacement, d = 150 cm = 1.5 m
Solution:
Displacement in the general form is represented by:
d = Asin(ωt ± α)
d = 3.2sin(2πft ± α)
d = 3.2sin(100πt ± α)
where,
A = 3.2 m,
ω = 2πf = 100π
Now,
at t = 0,
1.5 = 3.2sin(100π(0) ± α )
1.5 = 3.2sinα
sin α = = 0.4687
α = = 27.95° = 0.488 radian
Now, we can express displacement in the form of 'Asin(wt + α)' as:
d = 3.2sin(100πt ± 0.488 )
Answer:
Departure rate = 7.65 vehicle/min
Explanation:
See the attached file for the calculation.
