Function A:

. Vertical asymptotes are in the form x=, and they are a vertical line that the function approaches but never hits. They can be easily found by looking for values of <em>x</em> that can not be graphed. In this case, <em>x</em> cannot equal 0, as we cannot divide by 0. Therefore <em>x</em>=0 is a vertical asymptote for this function. The horizontal asymptote is in the form <em>y</em>=, and is a horizontal line that the function approaches but never hits. It can be found by finding the limit of the function. In this case, as <em>x</em> increases, 1/<em>x</em> gets closer and closer to 0. As that part of the function gets closer to 0, the overall function gets closer to 0+4 or 4. Thus y=4 would be the horizontal asymptote for function A.
Function B: From the graph we can see that the function approaches the line x=2 but never hits. This is the vertical asymptote. We can also see from the graph that the function approaches the line x=1 but never hits. This is the horizontal asymptote.
Answer:
(6, 3)
General Formulas and Concepts:
<u>Pre-Alg</u>
- Order of Operations: BPEMDAS
<u>Alg I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
4x = 8y
2x + 5y = 27
<u>Step 2: Rewrite systems</u>
x = 2y
2x + 5y = 27
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute: 2(2y) + 5y = 27
- Multiply: 4y + 5y = 27
- Combine like terms: 9y = 27
- Isolate <em>y</em>: y = 3
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Plug in y into an original equation to find x.</em>
- Substitute: 4x = 8(3)
- Multiply: 4x = 24
- Isolate <em>x</em>: x = 6
Answer:
7.28 in change
Step-by-step explanation:
When she used 20 bucks it gave her 7.28 cents.