<span>x + 3y= -11 (1)
</span><span>-9y = 33 + 3x ---->3x + 9y = -33 (2)
divide (2) equation by 2
</span>3x + 9y = -33
x + 3y = -11 (2')
and equation (1) is also x + 3y= -11 (1)
so
x + 3y= -11 (1)
x + 3y= -11 (2')
---------------------subtract
0 = 0
answer:
infinitely many solutions
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Answer:
Step-by-step explanation:
plz mark brainliest
The ratio of quarters to dimes is not still 5 : 3
<u>Solution:</u>
Given that ratio of quarters to dimes in a coin collection is 5:3 .
You add same number of new quarters as dimes to the collection .
Need to check if ratio of quarters to dimes is still 5 : 3
As ratio of dimes and quarters is 5 : 3
lets assume initially number of quarters = 5x and number of dimes = 3x.
Now add same number of new quarters as dimes to the collection
Let add "x" number of quarters and "x" number of dimes
So After adding,
Number of quarters = initially number of quarters + added number of quarters = 5x + x = 6x
Number of dimes = initially number of dimes + added number of dimes
= 3x + x = 4x
New ratio of quarters to dimes is 6x : 4x = 3 : 2
So we have seen here ratio get change when same number of new quarters and dimes is added to the collection
Ratio get change from 5 : 3 when same number of new quarters and dimes is added to the collection and new ratio will depend on number of quarters and dimes added to collection.
Answer:
the function is EVEN because f(x)= f(-x)
Step-by-step explanation:
Key to find if a function f(x) is even or odd is to replace the x with -x
if the results comes out to be f(x) then it is even function
if the results comes out to be -f(x) then it is odd function
where as graphically even f(x) will be symmetric around the y-axis and odd f(x) will be symmetric around the origin.
In given case f(x)=7
if we replace x with -x in above equation then results is 7
f(-x)= 7
hence f(x)= f(-x) = 7
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