1. Square of side= 6cm
2. Rectangle of side= 9cm x 4cm
3. Circle of radius is 6
Answer:
657m²
Step-by-step explanation:
use the provided formular and substitute the values
Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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Solve for the first variable in one the equations then substitute the result into the other equation so the answer is (2,5)
The answer should be found by rounding 376 to 380 and 266 to 270....you will get 650
