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Zarrin [17]
3 years ago
10

Find the mean for each set of data, weights of cats at a pet store in pounds: 5,4,10,7,6​

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
3 0

Answer:

6.4

Step-by-step explanation:

add all numbers together then divide by 5

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Solve :3(2x+1)^-1 + 5x=-1<br>​
Finger [1]

hope this is ans . Brother

8 0
3 years ago
Find all complex solutions of 5x^2+5x+3=0.
oksian1 [2.3K]

Answer:

see explanation

Step-by-step explanation:

5x² + 5x + 3 = 0 ← in standard form

with a = 5 , b = 5 , c = 3

Solve using the quadratic formula

x = \frac{-b+/-\sqrt{b^2-4ac} }{2a}

  = \frac{-5+/-\sqrt{5^2-(4(5)(3)} }{2(5)}

  = \frac{-5+/-\sqrt{25-60} }{10}

  = \frac{-5+/-\sqrt{-35} }{10}

  = \frac{-5+/-\sqrt{-1(35)} }{10}

 = \frac{-5+/-i\sqrt{35} }{10}

Then

x = \frac{-5}{10} ± \frac{1}{10} i\sqrt{35} , that is

x = - \frac{1}{2} - \sqrt{x} \frac{1}{10} i\sqrt{35} , - \frac{1}{2} + \frac{1}{10} i\sqrt{35}

5 0
3 years ago
Determine the x- and y- intercepts for the graph defined by the given equation.<br> y = 7x + 3
pantera1 [17]

Answer:

 intercept is 3 

X intercept is -3/7

5 0
3 years ago
Read 2 more answers
If the filling equipment is functioning properly what is the probability that the volume of oil in a randomly selected barrel wi
Sophie [7]

Answer:

P(X>55.4)=P(\frac{X-\mu}{\sigma}>\frac{55.4-\mu}{\sigma})=P(Z>\frac{55.4-55}{0.5})=P(Z>0.8)

P(Z>0.8)=1-P(Z\leq 0.8)

P(Z>0.8)=1-0.788=0.212

Step-by-step explanation:

Assuming this previous info : "Trucks carry barrels of crude oil from a port in Texas to a distributer in New Mexico on long  trailers. Filling equipment is used to fill the barrels with the oil. When functioning properly,  the actual volume of oil loaded into each barrel by the filling equipment at the port is  approximately normally distributed with a mean of 55 gallons and a standard deviation of 0.5  gallons. If the mean is greater than 55.4 gallons, the filling mechanism is overfilling."

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the amount filling of a population, and for this case we know the distribution for X is given by:

X \sim N(55,0.5)  

Where \mu=55 and \sigma=0.5

We are interested on this probability

P(X>55.4)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>55.4)=P(\frac{X-\mu}{\sigma}>\frac{55.4-\mu}{\sigma})=P(Z>\frac{55.4-55}{0.5})=P(Z>0.8)

And we can find this probability using the complement rule:

P(Z>0.8)=1-P(Z\leq 0.8)

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(Z>0.8)=1-0.788=0.212

8 0
3 years ago
(a) Tom says that 1/5 + 7/20 = 8/25
mezya [45]

numerator = top part of the fraction

denominator = bottom part of the fraction

* means multiply

a.

you can only add the numerator when the denominator is the same

cant add the denominator

denominator has to be the same

1/5 = 4/20

4/20 + 7/20 = 11/20

b.

1 7/8 = 15/8

3/4 ÷ 15/8 =

3/4 * 8/15 =

24/60 = divide both top and bottom by 12 =

2/5

7 0
3 years ago
Read 2 more answers
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