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Snezhnost [94]
3 years ago
11

The built in flash in a compact camera is usally capable of giving correct exsposure for distance up to how many meters?

Physics
1 answer:
Brut [27]3 years ago
8 0

Answer:

An on-camera flash is an indispensible accessory for many photographers; it provides additional light when conditions become too dark to handhold your camera comfortably, allows you to achieve more balanced exposures in daylight conditions, permits freezing of fast-moving subjects and can also be used to control or trigger other flash light sources. Additionally, a flash can be used as a highly effective creative tool to establish an aesthetic that elevates your imagery when lighting conditions are considered less than stellar. The benefits of an external on-camera flash far outweigh those provided by a built-in camera flash, while the only drawback is keeping an additional piece of equipment.

On-Camera Flash versus Off-Camera Flash versus In-Camera Flash

The term on-camera flash simply refers to a type of strobe light (flash) that can connect directly with your camera. While it is referred to as “on-camera” this does not require the flash to be physically mounted on your camera. On-camera flashes can, and often are, used off-camera. This differs from other strobe-light sources, such as studio pack strobes and monolights in that these types of strobes are not meant to be physically connected to your camera (except under rare and unusual circumstances involving convoluted methods of adaptation). Additionally, on-camera flashes usually have a self-contained power supply, although external power sources can sometimes be used to improve performance or battery life.

On-camera external flash also refers to the type of external flash that can be used on your camera, compared to a built-in flash that is integrated into many cameras. An on-camera external flash performs better than a built-in flash in almost every regard with the one exception that it is not built into your camera. The ability to take the flash off your camera results in a significantly greater number of lighting options; far more than simply providing a blast of flat light to the scene to facilitate an adequate exposure. It is often not desirable to have your flash pointed squarely at the scene at hand; more often than not you will want to bounce the flash light off other surfaces and point in other directions to control the look of your flash. When using an in-camera flash, you are forced to use the flash at the given angle from which it extends.

Most built-in flashes are also located near the camera lens, which can often result in the red-eye effect  when photographing subjects in dimly lit conditions. Red-eye occurs because pupils dilate in dim light, the built-in flash is aligned with the lens's optical axis, its beam enters the eye and reflects back at the camera from the retina at the rear of the eye, which is quite red. Being able to use an on-camera flash source off-camera, from a different angle, will help to eliminate the red-eye effect in your photographs of people.

Guide Numbers, Manual Usage, Controlling Flash Power and Sync Speeds

Before delving into the automatic technology that is contained within most contemporary flashes, it is best to understand how to manually control and grasp a flash’s power. This is directly related to having an understanding of exposure ratios—how shutter speeds and apertures affect and balance each other—even though auto-exposure metering is available and often utilized for determining the best exposure settings.

Explanation:

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21. A person standing 49.5m from the foot of a cliff claps his hands and hears an echo 0.3
777dan777 [17]

Answer:

330 m/s

Explanation:

The sound wave has to travel TO the cliff AND back = 2 * 49.5 = 99 m

magnitude of velocity =  distance / time = 99m / .3 s = 330 m/s

5 0
2 years ago
Who wrote the universal gravitation
ira [324]
I think it was Isaac Newton
3 0
3 years ago
A 64.1 kg runner has a speed of 3.10 m/s at one instant during a long-distance event.(a) What is the runner's kinetic energy at
Liono4ka [1.6K]

Answer:

(a)  the runner's kinetic energy at the given instant is 308 J

(b)  the kinetic energy increased by a factor of 4.

Explanation:

Given;

mass of the runner, m = 64.1 kg

speed of the runner, u = 3.10 m/s

(a) the kinetic energy of the runner at this instant is calculated as;

K.E_i = \frac{1}{2} mu^2\\\\K.E_i = \frac{1}{2}  \times 64.1 \times 3.1^2\\\\K.E_i = 308 \ J

(b) when the runner doubles his speed, his final kinetic energy is calculated as;

K.E_f = \frac{1}{2} mu_f^2\\\\K.E_f = \frac{1}{2} m(2u)^2\\\\K.E_f = \frac{1}{2} \times 64.1 \ \times (2\times 3.1)^2\\\\K.E_f = 1232 \ J

the change in the kinetic energy is calculated as;

\frac{K.E_f}{K.E_i} = \frac{1232}{308} =4

Thus, the kinetic energy increased by a factor of 4.

4 0
3 years ago
Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 12,900 kg. The thrust of its engines is
Alexandra [31]

Answer:

Acceleration a=0.5 m/s²

Explanation:

Given data

Mass m=12,900 kg=1.29×10⁴kg

Thrust of engine F=28,000 N=2.8×10⁴N

gravitational acceleration g=1.67 m/s²

To find

Acceleration

Solution

As we know  that

W_{weigth}=mg\\ W=(1.29*10^{4}kg )(1.67m/s^{2} )\\W=21543N

The net force can be given as

F_{net}=F_{thrust}-W\\F_{net}=(2.8*10^{4}-21543)N\\   F_{net}=6457 N

From Newtons second law of motion we know that

F=ma\\a=F/m\\a=\frac{6457N}{12,900kg}\\ a=0.5m/s^{2}

6 0
3 years ago
Who participates in sport more? women or men and why?
Katen [24]
More women ...........I'm not sure why
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4 years ago
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