The final velocity of the car is +1.5 m/s.
Explanation:
We have to divide the problem into two parts.
In the first part, the car starts from rest and accelerates for 5.0 s. We can find the final velocity of the car after this first part using the suvat equation:
where
v is the final velocity
u = 0 is the initial velocity
is the acceleration
t = 5.0 s is the time
Substituting,
In the second part, the brakes are applied, so the car decelerates for 3.0 s, and the final velocity is given by
where
v' is the final velocity
v = 7.5 m/s is the velocity at the beginning of this part
is the deceleration
t = 3.0 s is the time
Substituting,
So, the final velocity is +1.5 m/s.
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Answer could be2 grains of rice
The car is initially traveling north at 17.7 m/s, and after 12 s, its velocity is 14.1 m/s, still due north. This means that the direction of the car has not changed, so we can already say that the direction of the acceleration is north (if the magnitude of the acceleration is positive) or south (if the magnitude of the acceleration is negative).
To find the magnitude of the average acceleration, we must calculate the ratio between the change in velocity and the time taken:
Since the acceleration is negative, it means it is in the opposite direction to the motion of the car, therefore south. Therefore, the correct answer is
b) 0.30 m/s2, south
The magnitude of the object's velocity is
√ (5.1² + 2.82²) = √ (33.9624) = 5.828 m/s .
Kinetic energy = (1/2) (M) (speed²)
= (1/2) (5.22 kg) (5.828 m/s)²
= (2.61 kg) (33.9624 m²/s²)
= 88.64 kg-m²/s²
= 88.64 Joules
B. The electric potential at the given point from the proton is 2.7 x 10¹ volts
<h3>
Electric potential of the proton</h3>
The electric potential of the proton is calculated as follows;
V = kq/r
where;
- k is Coulomb's constant
- q is charge
- r is distance
V = (9 x 10⁹ x 1.6 x 10⁻¹⁹)/(5.3 x 10⁻¹¹)
V = 27.2 volts
V = 2.7 x 10¹ volts
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