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Andreyy89
3 years ago
6

If the mirror reflection coefficients for a laser resonator of length 5 m are 98.5% and 60%, and there are no losses, determine

the cavity threshold gain
Physics
2 answers:
slavikrds [6]3 years ago
4 0

Answer:

n sei

Explanation:

n seei

Irina-Kira [14]3 years ago
4 0

Answer:

i relly need help with points it  whould help if you make me brainliest

Explanation:

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You walk 6 m North and then 4 m south what distance did you travel? What is your displacement?
mestny [16]
<span>Distance is the actual path covered and displacement is the shortest distance from the object to the point of origin.

Distance is a total of 10m because you walked 6m initially and then another 4m. 6m + 4m = 10m

Displacement includes the starting point. You walked 6m North. Then you turned around and walked 4m South. Your total displacement is 2m because that is your current distance from the starting point.

Please mark as brainliest if satisfied with answer
</span>
6 0
3 years ago
An object starts at Xi = -4m with an initial velocity of 4m/s. It experiences an acceleration of -2 m/s^2 for 2 seconds, followe
GalinKa [24]

Answer:

a) 0 m/s

b) - 24 m/s

c)  - 68 m

Explanation:

Given:

Initial distance = - 4 m

Initial velocity, u = 4 m/s

1) acceleration, a = - 2 m/s² for time, t = 2 seconds

thus,

velocity after 2 seconds will be

from Newton's equation of motion

v = u + at

v = 4 + (-2) × 2

v = 0 m/s

2) Velocity after 2 second is the initial velocity for this case

given acceleration = - 6 m/s² for 4 seconds

thus,

final velocity, v = 0 + ( - 6 ) × 4 = - 24 m/s

here the negative sign depicts the velocity in opposite direction to the initial direction of motion

thus, velocity after 6 seconds = - 24 m/s

3) Now,

Total displacement in 6 seconds

= Displacement in 2 seconds + Displacement in 4 seconds

From Newton's equation of motion

s=ut+\frac{1}{2}at^2

where,  

s is the distance

u is the initial speed  

a is the acceleration

t is the time

thus,

= 0\times2+\frac{1}{2}\times(-2)\times2^2  + 0\times4+\frac{1}{2}\times-6\times4^2

= - 16 - 48

= - 64 m

Hence, the final displacement = - 64 - 4 = - 68 m

5 0
3 years ago
A hand pump is being used to inflate a bicycle tire that has a gauge pressure of 41.0 lb/in2. If the pump is a cylinder of lengt
damaskus [11]

Answer:

L - h = 12.3672 in

Explanation:

Given

P = 41.0 lb/in² = 41 P.S.I

L = 16.8 in

A = 3.00 in²

h = ?

In order that air flows into the tire, the pressure in the pump must be more than the tire pressure,  41.0  PSI.

We assume that air follows ideal gas equation, the temperature of the compressed air remains constant as the piston moves down. Taking one atmospheric pressure to be  14.6959  P.S.I , we can use the ideal gas equation

P*V = n*R*T

As number of moles of air do not change during its compression in the pump, n*R*T of the gas equation is constant. Therefore we have

P₁*V₁ = P₂*V₂    ⇒    V₂ = P₁*V₁ / P₂

where  

1  and  2  are initial and final states respectively,

V₁ = A*L = (3.00 in²)*(16.8 in)   ⇒   V₁ = 50.4 in³

P₁ = 14.6959  P.S.I

P₂ = P₁ + P = (14.6959 lb/in²) + (41.0 lb/in²) = 55.6959 lb/in²

Inserting various values we get

V₂ = (14.6959  P.S.I)*(50.4 in³) / (55.6959 lb/in²)

⇒  V₂ = 13.2985 in³

Length of pump, measured from bottom, this volume corresponds to is

h = V₂ / A  = (13.2985 in³) / (3.00 in²)

⇒  h = 4.4328 in

Piston must be pushed down by more than

L - h = 16.8 in - 4.4328 in = 12.3672 in

4 0
3 years ago
Cosmologist study ____
Firlakuza [10]
The origin and development of the universe
5 0
3 years ago
Read 2 more answers
The weight of a cuboid box is 288 N. Find its mass.​
zalisa [80]

Answer:

29.39 kg

Explanation:

From the question,

W = mg...................... Equation 1

Where W = weight of the cuboid box, m = mass of the cuboid box, g = acceleration due to gravity.

make m the subject of the equation

m = W/g.................. Equation 2

Given: W = 288 N

Constant: g = 9.8 m/s²

Substitute these values into equation 2

m = 288/9.8

m = 29.39 kg

4 0
3 years ago
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