Two golf balls are hit from the same point on a flat field. Both are hit at an angle of 55 degree above the horizontal. Ball 2 h
1 answer:
You might be interested in
Answer:
h=12.41m
Explanation:
N=392
r=0.6m
w=24 rad/s
So the weight of the wheel is the force N divide on the gravity and also can find momentum of inertia to determine the kinetic energy at motion
moment of inertia
Kinetic energy of the rotation motion
Kinetic energy translational
Total kinetic energy
Now the work done by the friction is acting at the motion so the kinetic energy and the work of motion give the potential work so there we can find height
Answer:
The coefficient of kinetic friction between the puck and the ice is 0.11
Explanation:
Given;
initial speed, u = 9.3 m/s
sliding distance, S = 42 m
From equation of motion we determine the acceleration;
v² = u² + 2as
0 = (9.3)² + (2x42)a
- 84a = 86.49
a = -86.49/84
|a| = 1.0296
= ma
where;
Fk is the frictional force
μk is the coefficient of kinetic friction
N is the normal reaction = mg
μkmg = ma
μkg = a
μk = a/g
where;
g is the gravitational constant = 9.8 m/s²
μk = a/g
μk = 1.0296/9.8
μk = 0.11
Therefore, the coefficient of kinetic friction between the puck and the ice is 0.11
Answer:
1.24611
Explanation:
V = Velocity = 10 ft/s
L = Length = 2 ft
g = Acceleration due to gravity = 32.2 ft/s²
Froude number is given by
Converting to SI units
The Froude number is 1.24611
The Froude number is equal. The Froude number is dimensionless as the units cancel each other. In order for this to happen the units used need to be consitent either imperial or SI.