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ahrayia [7]
3 years ago
7

Evaluate A ^2 for A = 2.3.__________________________________

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
4 0

Answer:

5.29

Step-by-step explanation:

<u>Step 1:  Substitute 2.3 for A</u>

(a)^2

(2.3)^2

<em>5.29</em>

Answer:  5.29

Ratling [72]3 years ago
3 0

Answer:4.6

Step-by-step explanation:I say 4.6

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5 0
3 years ago
141/2 write each expression in radical form
saveliy_v [14]

Answer:

70 1/2

Step-by-step explanation:

141/2 can be simplified in 70 1/2 as radical form

8 0
4 years ago
The area of a square garden is 50 m3. How long is the diagonal?
katen-ka-za [31]

Answer:

10 m

Step-by-step explanation:

If the area of a square is 50 m2, then the length of each side will be \sqrt{50} m, to get the diagonal length, after dividing the square by joining the points of the diagonal with a line, it forms two right angles with length \sqrt{50} m each.

the diagonal length represent the hypotenuse side of each of the right angle, knowing the pythagoras theorem:

(hyp)^{2} = (opp)^{2}   + (Adj)^{2}, so we have:

(diagonal)^{2}  = 50 + 50

(diagonal)^{2}  = 100

diagonal = 10 m

6 0
3 years ago
Function G is defined by g(x)=3(x+8).What is the value of G(12)
IrinaVladis [17]

Answer:

Step-by-step explanation:

g(x) = 3(x + 8).....find g(12).....what ur basically doing is subbing in 12 for x

g(12) = 3(12 + 8)

g(12) = 3(20)

g(12) = 60 <===

8 0
3 years ago
Read 2 more answers
Given 1+cosx\sinx+sinx\1+cosx=4, find a numerical value of one trigonometric function of x.
Len [333]

Answer:

Option d. sin(x)=\frac{1}{2}

Step-by-step explanation:

<u><em>The complete question is</em></u>

Given (1+cosx)/(sinx) + (sinx)/(1+cosx) =4, find a numerical value of one trigonometric function of x.

a. tanx=2

b. sinx=2

c. tanx=1/2

d. sinx=1/2

we have

\frac{1+cos(x)}{sin(x)}+\frac{sin(x)}{1+cos(x)}=4

Find the common denominator and adds the fractions

\frac{(1+cos(x))^2+sin^2(x)}{(1+cos(x))sin(x)}=4

Expanded the numerator

\frac{(1+2cos(x)+cos^2(x)+sin^2(x)}{(1+cos(x))sin(x)}=4

Remember that

sin^2(x)+cos^2(x)=1 ----> trigonometric identity

substitute

\frac{1+2cos(x)+1}{(1+cos(x))sin(x)}=4

\frac{2+2cos(x)}{(1+cos(x))sin(x)}=4

Factor 2 in the numerator

\frac{2(1+cos(x))}{(1+cos(x))sin(x)}=4

Simplify

\frac{2}{sin(x)}=4

sin(x)=\frac{1}{2}

7 0
3 years ago
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