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Mazyrski [523]
3 years ago
13

URGENT! When we solve (cos²x - 1 = 0) by adding and taking the square root, how come we get the same answer when we factor (cos²

x - 1) and use the zero product property to find the solution?
Mathematics
1 answer:
zysi [14]3 years ago
3 0

Answer:

It is the same answer because you still have the same x-1 and he exponent of 2. It doesn't matter about the zero unless you are trying to find the angle of a triangle.

Step-by-step explanation:

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2b^2+4b-2=0\\
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(b+1)^2=2\\
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