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DerKrebs [107]
2 years ago
12

A game of chance is played with a deck of 100 cards, numbered from 1 to 100. If 1 to 50 is drawn, the player wins $0. If 51 to 8

0 is
drawn, the player wins $7. If 81 to 100 is drawn, the player wins $9. If each play of the game cost $5, what is the expected payoff?
A)
-$3.90
B)
-$1.10
C)
$1.10
D)
$3.90
Mathematics
1 answer:
Lelu [443]2 years ago
3 0

Answer: -$1.10

Step-by-step explanation:

Expected value=(0)50/100+(7)30/100+(9)20/100= 3.90-5= -1.10

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Step-by-step explanation:

a. For sample where no preliminary estimate is given, the minimum sample size is calculated using the formula:

n=p(1-p)(\frac{z}{ME})^2

Where:

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n=0.5(1-0.5)\times (2.576/0.02)^2\\\\=4147.36\approx 4148

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b. If given a preliminary estimate p=0.38, we use the same formula but substitute p with the given value:

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Hence, the actual sample size is smaller for a known proportion from prior a prior study.

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