Question

Choose the correct value of x AND the correct value of y from the choices below.

Answer 1

Answer:

x = $\frac{16}{\sqrt{2} }$ and y = $\frac{16}{\sqrt{2} }$

Step-by-step explanation:

Applying the trigonometric functions to the given triangle;

i. To determine the value of x;

Sin θ = $\frac{opposite}{hypotenuse}$

Sin 45 = $\frac{x}{16}$

x = 16 * Sin 45

  = 16 * $\frac{1}{\sqrt{2} }$

x  = $\frac{16}{\sqrt{2} }$

ii. To determine the value of y;

Cos θ = $\frac{adjacent}{hypotenuse}$

Cos 45 = $\frac{y}{16}$

y = 16 * Cos 45

  = 16 * $\frac{1}{\sqrt{2} }$

y  = $\frac{16}{\sqrt{2} }$

Thus, x = $\frac{16}{\sqrt{2} }$ and y = $\frac{16}{\sqrt{2} }$