Based in your question that ask to evaluate the integral of tan^2(x)sec(x), base on my calculation and the use of the integral procedures and formula i came up with a solution that could answer your question and the evaluated answer is <span>tan(x)sec(x)−∫(<span>sec2</span>(x)−1)sec(x)dx</span>
This conic section is an ellipse.
Here: 2a = 10 ( the major axis ) and 2 b = 6 ( the minor axis );
and the formula is:
x² / a² + y² / b² = 1
So: a = 10 : 2 = 5 and b = 6 : 2 = 3.
x² / 5² + y² / 3² = 1
Answer:
The equation is: x² / 25 + y² / 9 = 1.
The area is 11.7 ft^2
good luck
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
