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elixir [45]
3 years ago
6

A boat travels 2km upstream and 2km downstream. The total time of the trip is 1 hour. The speed of the stream is 2km/h. What is

the speed of the boat in still water?
Mathematics
1 answer:
scoray [572]3 years ago
7 0
2 = ( v + 2 ) × t1 ;
2 = ( v - 2 ) × t2 ;
t1 + t2 = 1 ;
where v is the speed of the boat in still water ; t1 is the time upstream ; t2 is the tome downstream ;
Then, v + 2 = 2 / t1 and v - 2 = 2 / t2 ;
v = 2 / t1   -  2  and v = 2 / t2  +  2 ;
2 / t1 - 2 = 2 / t2 + 2 ;
2 / t1 - 2 / t2 = 4 ;
1 / t1 - 1 / t2 = 2 ;
t2 - t1 = 2t1t2 ;
But, t2 = 1 - t1 ;
1 - t1 - t1 = 2t1( 1 - t1 ) ;
1 - 2t1 = 2t1 - 2t1^2 ;
2t1^2 - 4t1 + 1 = 0 ; quadratic equation ;
solving this equation , 
t1 ≈ 0.29 hour ;
v ≈ 2 / 0.29 - 2;
v ≈ 4.89 km/h ;

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if in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99%
Dahasolnce [82]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The lifetime (in hours) of a 60-watt light bulb is a random variable that has a Normal distribution with σ = 30 hours. A random sample of 25 bulbs put on test produced a sample mean lifetime of = 1038 hours.

If in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99% confidence, how many randomly selected 60-watt light bulbs should be tested to achieve this result?

Given Information:

standard deviation = σ = 30 hours

confidence level = 99%

Margin of error = 6 hours

Required Information:

sample size = n = ?

Answer:

sample size = n ≈ 165

Step-by-step explanation:

We know that margin of error is given by

Margin of error = z*(σ/√n)

Where z is the corresponding confidence level score, σ is the standard deviation and n is the sample size

√n = z*σ/Margin of error

squaring both sides

n = (z*σ/Margin of error)²

For 99% confidence level the z-score is 2.576

n = (2.576*30/6)²

n = 164.73

since number of bulbs cannot be in fraction so rounding off yields

n ≈ 165

Therefore, a sample size of 165 bulbs is needed to ensure a margin of error not greater than 6 hours.

3 0
3 years ago
Y=x+2 2x-y=-4 Solve the systems of equations
larisa86 [58]

Answer:

Step-by-step explanation:

Given that,

y=x+2 equation 1

2x-y=-4 equation 2

This is a simultaneous equation.

Substitute equation 1 into equation 2

2x-y=-4. Since y=x+2

2x-(x+2) = -4

2x-x-2 = -4

x-2 = -4

x = -4+2

x = -2

Also from equation 1

y=x+2

Since x=-2

y=-2+2

y=0

Then, solution (x, y) = (-2,0)

4 0
3 years ago
Read 2 more answers
Judy is playing a card game. She needs to select two cards below that have a sum greater
Zielflug [23.3K]

Answer:

2\frac{2}{5}  + 2\frac{5}{8} \simeq 5

2\frac{2}{7}  + 2\frac{5}{8}  \simeq 5

Step-by-step explanation:

Mixed fraction a\frac{b}{c} can be converted into like or unlike fractions.

Here, a\frac{b}{c} =  \frac{ac +b}{b}

So, convert all the given fractions as follows:

2\frac{2}{5} =  \frac{2(5) +2}{5} = \frac{12}{5}  =2.4

2\frac{2}{7} =  \frac{2(7) +2}{7} = \frac{16}{7}  =2.4

1\frac{7}{8} =  \frac{1(8) +7}{8} = \frac{15}{8}  =1.8

2\frac{1}{10} =  \frac{2(10) + 1}{10} = \frac{21}{10}  =2.1

2\frac{5}{8} =  \frac{2(8) +5}{8} = \frac{21}{8}  =2.6

Here, No Two fractions on addition gives a sum greater than 5.

But an approximate sum of 5 is given by adding 2.4 + 2.6 = 5

⇒2\frac{2}{5}  + 2\frac{5}{8} \simeq 5

or  ⇒2\frac{2}{7}  + 2\frac{5}{8}  \simeq 5

7 0
3 years ago
Whats the answer i have no idea
VMariaS [17]

Answer:

1 over 8

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Write an equation for the line passing through the points (-5,15) and (20,25). Show how you found your answer.
olasank [31]

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-5, 15) and (20, 25). substitute:

m=\dfrac{25-15}{20-(-5)}=\dfrac{10}{25}=\dfrac{2}{5}\\\\y-15=\dfrac{2}{5}(x-(-5))\\\\y-15=\dfrac{2}{5}(x+5)\qquad|\text{use distributive property}\\\\y-15=\dfrac{2}{5}x+2\qquad|\text{add 15 from both sides}\\\\y=\dfrac{2}{5}x+17\qquad|\text{multiply both sides by 5}\\\\5y=2x+85\qquad|\text{subtract 2x from both sides}\\\\-2x+5y=85\qquad|\text{change the signs}\\\\2x-5y=-85

Answer:

point-slope form: y-15=\dfrac{2}{5}(x+5)

slope-intercept form: y=\dfrac{2}{5}x+17

standard form: 2x-5y=-85

7 0
3 years ago
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