Answer:
- as written, c ≈ 0.000979 or c = 4
- alternate interpretation: c = 0
Step-by-step explanation:
<em>As written</em>, you have an equation that cannot be solved algebraically.
(32^2)c = 8^c
1024c = 8^c
1024c -8^c = 0 . . . . . . rewrite as an expression compared to zero
A graphical solution shows two values for c: {0.000978551672551, 4}. We presume you're interested in c = 4.
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If you mean ...
32^(2c) = 8^c
(2^5)^(2c) = (2^3)^c . . . . rewriting as powers of 2
2^(10c) = 2^(3c) . . . . . . . simplify
10c = 3c . . . . . . . . . . . . . .log base 2
7c = 0 . . . . . . . . . . . . . . . subtract 3c
c = 0 . . . . . . . . . . . . . . . . divide by 7
This answer is A, first you subtract 3x from both sides simplify 8x-9-3x to 5x-9, add 9 to both sides, simplify 4+9 to 13, divided both sides by 5 and you’ll get 2.6
Answer:
f(x)= 2x^4 - x^3=24 -18x^2 + 9x= 45 45-24=21
Step-by-step explanation:
just multipkye that
Answer:
Step-by-step explanation:
Standard equation of an ellipse,

(h, k) is the center of the ellipse
Value of a = Distance of the center from the vertex
b = Distance of the center from the covertex
From the picture attached,
a = Distance of the center (h, k) from the vertex (2, -2) = 3 units
b = Distance of the center (h, k) from the co-vertex (-1, 0) = 1 unit
Center of the ellipse (h, k) = (-1, -2)