The two real values that are not in the domain of the composition are x = 2 and x = -2.
<h3>
What two numbers are not in the domain of f°g?</h3>
Here we have:
f(x) = 1/x
g(x) = x^2 - 4
The composition is:
f°g = f(g(x)) = 1/(x^2 - 4)
The two values that are not in the domain are the values of x such that g(x) = 0, because we can't divide by zero.
g(x) = 0 = x^2 - 4
4 = x^2
±√4 = x
±2 = x
So g(x) = 0 when x = 2 or x = -2, so these are the two real values that are not in the domain of f°g.
If you want to learn more about domains:
brainly.com/question/1770447
#SPJ1
Step-by-step explanation:
(92-3)x2=184 is the answer
Answer:
(-5,-3)
Step-by-step explanation:
In this case to find the solution you could use substitution. This way you can solve without changing the equation over again.
(b - 2) - 3b = 4
b - 2 - 3b = 4
-2b - 2 = 4
-2b = 6
b = -3
Plug back in to find value a
a = (-3) - 2
a = -5
Check your answer before submitting
(-5) - 3(-3) = 4
-5 + 9 = 4
4 = 4
Hope this helps
Answer:
no
Step-by-step explanation:
If x = 3 is a zero, then f(3) = 0
f(3)
= 4
- 3³ - 52(3)² - 35(3) + 12
= 324 - 27 - 468 - 105 + 12
= - 264
Since f(3) ≠ 0 then x = 3 is not a zero of f(x)
350 gallons for 9
Car with 15 gallons is 427.5 miles and a motorcycle with 5 is 320 so he is wrong
