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Neporo4naja [7]
3 years ago
15

What is (6x-5) + (8x-50)

Mathematics
2 answers:
iris [78.8K]3 years ago
5 0

6x + 8x - 5 - 50 \\  =  > 14x - 55

kvasek [131]3 years ago
4 0

Answer:

14x - 55

Step-by-step explanation:

6x - 5 = 8x - 50

6x + 8x = 14x -5-50

-5- 50 = -55

14x -55

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Arc length = radius x central angle in radians.

Answer you seek : is 2 or B : pie inches

Step-by-step explanation:

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3 years ago
Omar have 2 closet with 3 shelve and 5 backpacks on each shelve
Gekata [30.6K]

Step-by-step explanation:

And he wants to know how many backpacks he has. Simple!

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5 0
3 years ago
20 POINTS!!! PLZ ANSWER!! On the moon, the time, in seconds, it takes for an object to fall a distance, d, in feet, is given by
scoundrel [369]

Answer:

Part a) f(2)=1.57\ sec

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) see the explanation

Part c) 2,165.43\ sec

Step-by-step explanation:

Let

f(d) -----> the time in seconds it takes for an object to fall

d -----> distance in feet

we have

f(d)=1.11\sqrt{d}

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we know that

f(2) represent the time in seconds it takes for an object to fall a distance of 2 feet

For d=2\ ft

substitute in the function above and solve for f(2)

f(2)=1.11\sqrt{2}

f(2)=1.57\ sec

therefore

It takes 1.57 seconds for an object to fall a distance of 2 feet

Part b) The imbrium basin is the largest basin on the moon. A reasonable domain for the height above the lowest point in the basin is given by {d|0 ≤ d ≤ 3805774}

What does this tell you about the basin?

The height of the basin is greater than or equal to 0 ft and less than or equal to 3,805,774 ft  

so

The maximum height of the basin is 3,805,774 ft

Part c) How long would it take a rock to drop from the rim to the bottom of the basin?

we know that

The distance from the rim to the bottom of the basin is equal to the maximum height of the basin

so

d=3,805,774\ ft

substitute the value of d in the function f(d)

f(d)=1.11\sqrt{3,805,774}

f(d)=2,165.43\ sec

3 0
3 years ago
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NeX [460]

Answer:

23

Step-by-step explanation:

i think

3 0
2 years ago
Un gusano está subiendo un postre que mide 2 metros de largo, en su ascenso, descansa cada 3 cm, pero por cada 3cm que avanza, r
kupik [55]
600/800 descansos porque mencionaste que se toma un descanso cada 3 cm pero se desliza 1 cm cada vez que se toma un descanso, así que solo cambia los 2 ma cm, que es 200 veces eso a 3 o 4 y obtendrás el número de descansos (acabo de adivinar)
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3 years ago
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