To solve quadratics, the most correct and effective way, in my opinion, is the quadratic formula:

<span><span>
Plugging it in, we get:
</span></span>

So the final answer is:

and
by the use of elimination method
make all coefficients of subject to be eliminated similar..by multiplying the coefficients with one another
for eqn(i)
5(-10y+9x=-9)
-50y+45x=-45
for eqn(ii)
9(10y+5x=-5)
90y+45x=-45
-50y+45x=-45
90y+45x=-45
...subtract each set from the other...
we get
-140y+0=0
y=0
from eqn(i)
10y+5x=-5
0+5x=-5
x= -1
The answer is 8/9 i believe.
Answer:
the least value would be 85
Step-by-step explanation:
Answer:
addition I hope this is right