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lakkis [162]
2 years ago
6

The students in Mr Taylor's class are part of different clubs.

Mathematics
2 answers:
natka813 [3]2 years ago
8 0

Answer:

The answer is D

Step-by-step explanation:

1 girl in reading club for 3 girls in a drama club

4 x 3 = 12

Have a good day and be safe.

Thepotemich [5.8K]2 years ago
4 0
I do believe the answer is D, sorry if that’s incorrect
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Step 1:
Set Variables (We will use x & y)

x = years
y = total orangutan population

Step 2:
Set up Equations

784 - 25x = y
817 - 36x = y

Step 3:
Set equations equal to each other & solve

784 - 25x = 817 - 36x
784 = 817 - 11x
-33 = -11x
3 years = x
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To sample the average number of pages for the books in the school library, the
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Which value of a would make the following expression completely factored?
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when it ur first question and u make it hard

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Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose t
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Answer and Step-by-step explanation: For an exponential distribution, the probability distribution function is:

f(x) = λ.e^{-\lambda.x}

and the cumulative distribution function, which describes the probability distribution of a random variable X, is:

F(x) = 1 - e^{-\lambda.x}

(a) <u>Probability</u> of distance at most <u>100m</u>, with λ = 0.0143:

F(100) = 1 - e^{-0.0143.100}

F(100) = 0.76

<u>Probability</u> of distance at most <u>200</u>:

F(200) = 1 - e^{-0.0143.200}

F(200) = 0.94

<u>Probability</u> of distance between <u>100 and 200</u>:

F(100≤X≤200) = F(200) - F(100)

F(100≤X≤200) = 0.94 - 0.76

F(100≤X≤200) = 0.18

(b) The mean, E(X), of a probability distribution is calculated by:

E(X) = \frac{1}{\lambda}

E(X) = \frac{1}{0.0143}

E(X) = 69.93

The standard deviation is the square root of variance,V(X), which is calculated by:

σ = \sqrt{\frac{1}{\lambda^{2}} }

σ = \sqrt{\frac{1}{0.0143^{2}} }

σ = 69.93

<u>Distance exceeds the mean distance by more than 2σ</u>:

P(X > 69.93+2.69.93) = P(X > 209.79)

P(X > 209.79) = 1 - P(X≤209.79)

P(X > 209.79) = 1 - F(209.79)

P(X > 209.79) = 1 - (1 - e^{-0.0143*209.79})

P(X > 209.79) = 0.0503

(c) Median is a point that divides the value in half. For a probability distribution:

P(X≤m) = 0.5

\int\limits^m_0 f({x}) \, dx = 0.5

\int\limits^m_0 {\lambda.e^{-\lambda.x}} \, dx = 0.5

\lambda.\frac{e^{-\lambda.x}}{-\lambda} = -e^{-\lambda.x} + e^{0}

1 - e^{-\lambda.m} = 0.5

-e^{-\lambda.m} = - 0.5

ln(e^{-0.0143.m}) = ln(0.5)

-0.0143.m = - 0.0693

m = 48.46

6 0
3 years ago
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