<span>The sub-boxes will have dimensions
x sub-intervals are 0 to 1 and 1 to 2. Midpoints are at

and </span><span>
y sub-intervals are 0 to 1 and 1 to 2. Midpoints are at </span><span>

and </span><span>
z sub-intervals are 0 to 1 and 1 to 2. Midpoints are at </span><span>

and </span><span><span>

</span>
Let


</span>
Step-by-step explanation:
Take the natural log of both sides:

Logarithm rules allow you to bring down the exponents:

Now differentiate. We will have to implicitly differentiate 'y' since it is a function of 'x'. Both sides require the product rule:

Isolate the terms that have y' since that is what we want:

Factor out y' to get:

Therefore:

Answer:
1
Step-by-step explanation:
of course the answer is one but you can't write it in exponential form because a regular keyboard doesn't contain it
Answer:
x/5+9
Step-by-step explanation:
Answer:
![\[y=-\frac{1}{2}x+\frac{5}{2}\]](https://tex.z-dn.net/?f=%5C%5By%3D-%5Cfrac%7B1%7D%7B2%7Dx%2B%5Cfrac%7B5%7D%7B2%7D%5C%5D)
Step-by-step explanation:
Equation of the given line: ![\[y=2x-3\]](https://tex.z-dn.net/?f=%5C%5By%3D2x-3%5C%5D)
Slope of the line = ![\[2\]](https://tex.z-dn.net/?f=%5C%5B2%5C%5D)
Slope of the perpendicular line = ![\[-\frac{1}{2}\]](https://tex.z-dn.net/?f=%5C%5B-%5Cfrac%7B1%7D%7B2%7D%5C%5D)
So the equation of the perpendicular line:
![\[y=-\frac{1}{2}x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D-%5Cfrac%7B1%7D%7B2%7Dx%2Bc%5C%5D)
This passes through the point (-1,2).Substituting in the equation:
![\[2=-\frac{1}{2}*(-1)+c\]](https://tex.z-dn.net/?f=%5C%5B2%3D-%5Cfrac%7B1%7D%7B2%7D%2A%28-1%29%2Bc%5C%5D)
=>
=> ![\[c=\frac{5}{2}\]](https://tex.z-dn.net/?f=%5C%5Bc%3D%5Cfrac%7B5%7D%7B2%7D%5C%5D)
So the equation of the line :
![\[y=-\frac{1}{2}x+\frac{5}{2}\]](https://tex.z-dn.net/?f=%5C%5By%3D-%5Cfrac%7B1%7D%7B2%7Dx%2B%5Cfrac%7B5%7D%7B2%7D%5C%5D)