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Valentin [98]
3 years ago
14

Find equation of the line shown

Mathematics
1 answer:
Keith_Richards [23]3 years ago
6 0

Answer:

y = x + 6

Step-by-step explanation:

y = mx + b

Since (0,6) is your y-intercept (or just positive 6), you have your <em>b</em> part of the equation solved.

The line goes up at a continuous rate of up 1, over 1, so they cancel each other out, making the <em>m </em>part of your equation 1.

So, you have y = 1x + 6 and you change it to just y = x + 6 (since x itself automatically has a 1 before it, when it's by itself).

Hope this helps!

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Give the first ten terms of the following sequences. You can assume that the sequences start with an index of 1. Logs are to bas
Vitek1552 [10]

Answer:

a)

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a4 = log(4) = 2 (2² = 4)

a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322

a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)

a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807

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a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322

b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:

log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that

a1 = 1

a2 = 2

a3 = 3

a4 = 4

a5 = 5

a6 = 6

a7 = 7

a8 = 8

a9 = 9

a10 = 10

I hope this works for you!!

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