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katen-ka-za [31]
3 years ago
10

What is the measure of angle ACB?

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
7 0

Answer:

Linear pair is a pair of adjacent angles formed when two lines intersect.

so, \angle EAB and \angle CAB are linear pairs.

Linear pairs are always supplementary.

therefore,

\angle EAB+\angle CAB=180^{\circ}              ......[1]

Also, it is given in figure, \angle EAB = 108^{\circ}

Substitute in [1], we get;

108^{\circ}+\angle CAB=180^{\circ}

Simplify:

\angle CAB =180^{\circ}-108^{\circ}=72^{\circ}

Exterior- Angle sum Property states that if the measure of an exterior angle of a triangle is equal to the sum of the measures of the two non-adjacent interior angles of the triangle.

then by Exterior angle sum property ;

\angle ACB+\angle CAB =\angle CBF

Substitute the values given in the figure;

\angle ACB+72^{\circ}=145^{\circ}

simplify;

\angle ACB =145-72 = 73^{\circ}

therefore, the measure of angle ACB is, 73^{\circ}



Gala2k [10]3 years ago
5 0
The answer is 73 degrees.... A triangle adds up to 180 degrees. The angle next  to  B is a supplementary angle so you subtract 180 - 145= 35.... angle next to A is also supplementary so you 180 - 108 = 72

72 + 35 = 107
180 - 107= 73

Your answer is 73 degrees

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(-4,-6) and (3,-7) find the distance between each pair of points
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Answer:

5\sqrt{2}

Step-by-step explanation:

distance between two points:

d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}

we have:

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x_{1} = -4

y_{1} =-6

x_{2} = 3

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so we have:

d =\sqrt{(3-(-4))^{2}+ (-7-(-6))^{2}}\\\\d =\sqrt{(7)^{2}+ (-1)^{2}}\\\\d = \sqrt{49+ 1}\\\\d=\sqrt{50}\\\\d=5\sqrt{2}

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3 years ago
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1 year ago
In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0
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If a coin is flipped 20 times and a head comes up 7 times, what is the relative frequency of a head coming up?
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Relative frequency: 7 / 20 = 0.35, which is the option B.
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