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3 years ago

What is gcd of numbers like (n^13-n)?

Mathematics

1 answer:

arsen [322]3 years ago

3 0

Answer:

GCD( $n^{13},n)$ =n

Step-by-step explanation:

We are given that two numbers $n^{13}$ and n

We have to find the gcd of two given numbers

GCD: It is also called HCF. It is defined as the highest common facotors of two more numbers.

To find the gcd of two given numbers first we find the factor of two numbers then we find highest common factors .

$n^{13}=n\timesn\times n\times n......\times n$ ( 13 times )

Factors of $n^{13}$ are 1,n,n,n....n(13 times)

$n=1\timesn$

Factors of n are 1,n

Common factors of two given numbers are 1 ,n

Highest common factor of two given numbers is n.

Therefore, gcd of two given numbers is n.

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At what point of the curve y = cosh(x does the tangent have slope 2?

Dahasolnce [82]

The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444

Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44

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3 years ago

1.A bag has 4 green blocks, 3 red blocks, 2 blue blocks, and 1 yellow block. Find the probability of randomly selecting a block

maks197457 [2]

Answer: 1) 7/10 2) 15 3) 240 4) 1/4 5) 4/9 6) 1/20 7) No, not independent

Step-by-step explanation:

1. 4 green+3red+2blue+1yellow = 10 total

if 3/10 are red, then 7/10 are not red. So the second option, 7/10

2. 3 cartons in every 40

40*5 = 200

so do 3*5 = 15

so 15 or the third option

3. 40 out of 110

110*6 = 660

so do 40*6 = 240

so 240 or the fourth option

Flipping heads: 1/2

rolling even: well, there is 2, 4, and 6, or 3 even numbers so 3/6 or 1/2

do 1/2*1/2 = 1/4

so 1/4 or the third option

5. Numbers more than 2: 3, 4, 5, 6 (4 numbers)

4/6 or 2/3 chance the first time, 2/3 chance the second time

do 2/3*2/3 = 4/9

so 4/9 or the second option

6. 5 dishes and 4 desserts

1/5 chance of picking the dish

1/4 chance of picking the dessert

do 1/5*1/4 = 1/20

so 1/20 or the fourth option

7. Since you don’t replace the marble after picking it, it affects the outcome of the second draw. Therefore the events are dependent, or not independent. So the second option.

7 0

3 years ago

Z - 12 = 6 A. 10 B. 15 C. 18 D. 6 Need help working it out

const2013 [10]

Z-12=6

you take the 12 and add it to both sides making it look like:
z-12+12=6+12
which also looks like
z-0=6+12

z-0 = z

so now you have
z=6+12

6+12 = 18

SO Z=18!!!

your answer is 18

8 0

2 years ago

Read 2 more answers

You are testing the claim that the mean GPA of night students is different from the mea GPA of day students. You sample 20 night

svetlana [45]

Answer:

As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.

Step-by-step explanation:

Here n= 20

Sample mean GPA = x`= 2.84

Standard mean GPA = u= 2.55

Standard deviation = s= 0.45.

Level of Significance.= ∝ = 0.01

The hypothesis are formulated as

H0: u1=u2 i.e the GPA of night students is same as the mean GPA of day students

against the claim

Ha: u1≠u2

i.e the GPA of night students is different from the mea GPA of day students

For two tailed test the critical value is z ≥ z∝/2= ± 2.58

The test statistic

Z= x`-u/s/√n

z= 2.84-2.55/0.45/√20

z= 0.1441

As the calculated value of z does not lie in the critical region the null hypothesis is accepted that the GPA mean of the night students is the same as the GPA mean of the day students.

8 0

3 years ago

Ask a 1 grade question and my brother will answer it

Sliva [168]

10 +10 good luck have fun

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4 years ago

Read 2 more answers