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3 years ago

What is gcd of numbers like (n^13-n)?

Mathematics

1 answer:

arsen [322]3 years ago

3 0

Answer:

GCD( $n^{13},n)$ =n

Step-by-step explanation:

We are given that two numbers $n^{13}$ and n

We have to find the gcd of two given numbers

GCD: It is also called HCF. It is defined as the highest common facotors of two more numbers.

To find the gcd of two given numbers first we find the factor of two numbers then we find highest common factors .

$n^{13}=n\timesn\times n\times n......\times n$ ( 13 times )

Factors of $n^{13}$ are 1,n,n,n....n(13 times)

$n=1\timesn$

Factors of n are 1,n

Common factors of two given numbers are 1 ,n

Highest common factor of two given numbers is n.

Therefore, gcd of two given numbers is n.

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Which of the following is a like radical to RootIndex 3 StartRoot 7x EndRoot?

lana [24]

Answer:

A. 4 (RootIndex 3 StartRoot 7 x EndRoot) or $4(\sqrt[3]{7x})$

Step-by-step explanation:

Given:

A radical whose value is, $r_1=\sqrt[3]{7x}$

Now, we need to find the like radical for $r_1$ .

Let the like radical be $r_2$ .

As per the definition of like radicals, like radicals are those that can be expressed as multiples of each other.

So, if two radicals $r_1\ and\ r_2$ are like radicals, then

$r_1 = n \times r_2
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Where, 'n' is a real number.

Here, $r_1=\sqrt[3]{7x}$

Now, let us check all the options .

Option A:

4 (RootIndex 3 StartRoot 7 x EndRoot) or $r_2=4\sqrt[3]{7x}$

Now, we observe that $r_2$ is a multiple of $r_1$ because

$r_2=4\times \sqrt[3]{7x}\\\\ r_2=4\times r_1..............(r_1=\sqrt[3]{7x})$

Therefore, option A is correct.

Option B:

StartRoot 7 x EndRoot or $r_2=\sqrt{7x}$

As the above radical is square root and not a cubic root, this option is incorrect.

Option C:

x (RootIndex 3 StartRoot 7 EndRoot) or $r_2=x\sqrt[3]{7}$

As the term inside the cubic root is not same as that of $r_1$ , this option is also incorrect.

Option D:

7 StartRoot x EndRoot or $r_2=7\sqrt{x}$

As the above radical is square root and not a cubic root, this option is incorrect.

Therefore, the like radical is option (A) only.

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WILL MARK AS BRAINLIEST 4. Suppose there is a card game where you are dealt a hand of three cards. You have already learned that

Alexeev081 [22]

Answer:

Part A- 6

Part B- 3

Part C- 3/22100

Step-by-step explanation:

Part A-

Use the permutation formula and plug in 3 for n and 2 for k.

nPr=n!/(n-k)!

3P2=3!/(3-2)!

Simplify.

3P2=3!/1!

3P2=6

Part B-

Use the combination formula and plug in 3 for n and 2 for k.

nCk=n!/k!(n-k)!

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Simplify.

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Part C-

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3 years ago

An airplane is traveling at a speed of 200 km/h. Compute the speed of the airplane in m/s.

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use 1 km = 1000 meter

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