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Nutka1998 [239]
3 years ago
5

What is gcd of numbers like (n^13-n)?

Mathematics
1 answer:
arsen [322]3 years ago
3 0

Answer:

GCD(n^{13},n)=n

Step-by-step explanation:

We are given that two numbers n^{13} and n

We have to find the gcd of two given numbers

GCD: It is also called HCF. It is defined as the highest common facotors of two  more numbers.

To find the gcd of two given numbers first we find the factor of two numbers then we find highest common factors .

n^{13}=n\timesn\times n\times n......\times n( 13 times )

Factors of n^{13}are 1,n,n,n....n(13 times)

n=1\timesn

Factors of n are 1,n

Common factors of two given numbers are 1 ,n

Highest common factor of two given numbers  is n.

Therefore, gcd of two given numbers is n.

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Answer:

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Step-by-step explanation:

If the variation is proportional dividing the y-value by the x-value will give the same result for all table entries. That quotient is the constant of variation (k).

Here 6.4/4 = 11.2/7 = 16/10 = 20.8/13 = 1.6

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<em><u>Solution:</u></em>

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We have to solve the given inequality

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