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IgorC [24]
3 years ago
14

Find the area of a polygon with vertices at (1,3), (7,3), (7,7), and (4,7).

Mathematics
2 answers:
Natasha2012 [34]3 years ago
8 0

(1,3) and (7,3) falls on the same horizontal line. hence, the distance is just equal to 6 units. (7,3) and (7,7) meanwhile lie on the same vertical line. hence the distance is 4. (7,7) and (4,7) lie on the same horizontal line with a distance of 3. 

Finally, to get back to point (1,3) - (4,7) ----> (1,3), 3 to the left and 4 down, the diagonal being 5. 
6+4+3+5= 10 + 8 = 18.
fenix001 [56]3 years ago
7 0
I graphed the points and connected them. I found two shapes. A rectangle and a right triangle.

I individually computed its area.

Rectangle = length * width = 4 * 3 = 12 square units

Triangle = ab/2 = (4 * 3) / 2 = 12/2 = 6 square units

12 + 6 = 18 square units
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Find the sum of the following series. Round to the nearest hundredth if necessary,
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For altitudes up to 36,000 feet, the relationship between ground temperature and atmospheric
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The equation for a is a=-\frac{2000}{7}*(t-g)

The altitute is 101,428.57 feet

Step-by-step explanation:

You know that the relationship between ground temperature and atmospheric  temperature can be described by the formula

t = -0.0035a +g

where:

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Solving the equation for a:

-0.0035a +g=t

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a=\frac{t-g}{-0.0035}

a=-\frac{2000}{7}*(t-g)

<u><em>The equation for a is </em></u>a=-\frac{2000}{7}*(t-g)<u><em></em></u>

If the atmospheric temperature is -305 °F and the ground temperature is 50 °F, then t= -305 °F and g= 50 °F

Replacing in the equation for a you get:

a=-\frac{2000}{7}*(-305-50)

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<u><em>The altitute is 101,428.57 feet</em></u>

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