Answer:
-8n + 9
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
A = -3n + 2
B = 5n - 7
A - B
<u>Step 2: Simplify</u>
- Substitute: -3n + 2 - (5n - 7)
- Distribute negative: -3n + 2 - 5n + 7
- Combine like terms (n): -8n + 2 + 7
- Combine like terms (Z): -8n + 9
Yes it does have a great day
Answer:
120
Step-by-step explanation:
Add more detail if it is a different question
Answer:
<u>a(n)=80*(9/10)^(n-1)</u>
Step-by-step explanation:
I think u r confused
this sequence is geometric not arithmetic
HOw we know that ??
when we get a common difference <u>that must Be equal </u>
d=72-80=-8 not equal to d=64.8-72=-7.2
So it is not arithmetic
but when we get the common ratio that also must <u>be equal </u>
r=72/80=9/10 equal to r=64.8/72=9/10
So it is geometric
By using this equation:
a(n)=a*r^(n-1)
and we have <u>a=80 , r=9/10</u>
Then <u>a(n)=80*(9/10)^(n-1)</u>
<em>I really hope this helps <3</em>
Answer:
A) (1 s, 2.3 s)
B) (-4 m/s², 3.8 m/s²)
Step-by-step explanation:
The car's position which is the distance is given by the equation;
s(t) = t³ - 5t² + 7t
A) Velocity is the first derivative of the distance. Thus;
v(t) = ds/dt = 3t² - 10t + 7
At v = 0, we have;
3t² - 10t + 7 = 0
Using quadratic formula, we have;
t = 1 and t = 2.3
Thus, time at velocity of 0 is t = (1 s, 2.3 s)
B) acceleration is the derivative of the velocity. Thus;
a(t) = dV/dt = 6t - 10
At velocity of 0, we got t = 1 and t = 2.3
Thus;
a(1) = 6(1) - 10 = -4 m/s²
a(2.3) = 6(2.3) - 10 = 3.8 m/s
Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)