For the first example given the answer would be No. you have a 4 mile head start. at the 4 mile line, your friend starts at 8 miles an hour and you start running at 6 miles an hour. basic addition should give the answer. In one hour time, you wouldve ran 6 miles plus the 4 you had as a head start, giving you the 10 miles you needed to reach the finish line. He on the other hand, Biked 8 miles in an hour time. By that time, you had just reached the finish line.
So the answer is no for the first example
For the second example the maths get bit harder. You start at the 5 mile point and you friend starts at the beginning point. You only need 5 miles to win, and your friend needs double (its actually more than double, because if it was perfectly doubled, you would tie the race. Your pace just has to be a bit more than half of his speed. his speed is 17mph. yours, by logic, needs to be even a tad bit more than 8.5mph. You need to have a faster speed than 8.5mph (8.51mph works perfectly) and you win by a hair. But when we se your example, you're only going at 7mph. A whole mile and a half behind pace. Sadly, he passes you short before winning.
The second example is YES he does pass you before the end of the trail.
<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helped</u></em><em><u>.</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>spent</u></em><em><u> </u></em><em><u>around</u></em><em><u> </u></em><em><u>20</u></em><em><u> </u></em><em><u>minutes</u></em><em><u> </u></em><em><u>writing</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>answer</u></em><em><u>,</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>5</u></em><em><u> </u></em><em><u>star</u></em><em><u>,</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>noter</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>"</u></em><em><u>BRAINLIEST</u></em><em><u> </u></em><em><u>ANSWER"</u></em><em><u> </u></em><em><u>would</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>very</u></em><em><u> </u></em><em><u>much</u></em><em><u> </u></em><em><u>apreciated</u></em><em><u>!</u></em><em><u> </u></em><em><u>H</u></em><em><u>a</u></em><em><u>ve</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>good</u></em><em><u> </u></em><em><u>day</u></em><em><u>!</u></em><em><u>!</u></em>
Answer:
6/16, perhaps?
Good luck! And if you could, please mark me brainliest. :)
Answer:
factor -6 out of -6y - 18
Step-by-step explanation:
honestly i got it off of a math website that i use, all of my answers from it are usually correct but if it's wrong feel free to delete it
