(1/2)(1/2)(1/2)(1/2)= 1/16 or 6.25%
The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.
Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s
The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.
Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s
When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.
Answer: 7 s
Answer:
A : 4x+5x=180
Step-by-step explanation:
They form a linear pair which equals 180.
Answer:
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Answer:
100
Step-by-step explanation:
Isosceles triangle have 2 equal angles. Therefore the second angle in the triangle will also be 25.
Since the sum of angles in a triangle is 180.
180-(25x2) will give you the last angle in one of the triangles.
The other angle is identical so the angle at the top of the other triangle will also be 130.
The sum of angles in a circle is 360.
Therefore, angle x = 360-(130x2)
X= 100