All categories

3 years ago

Determine the graph of the polar equation r =6/2-2cos theta (picture provided)

Mathematics

1 answer:

vredina [299]3 years ago

5 0

Answer:

Choice D is correct

Step-by-step explanation:

The first step is to write the polar equation of the conic section in standard form by dividing both the numerator and the denominator by 2;

$r=\frac{3}{1-cos(theta)}$

The eccentricity of this conic section is thus 1, the coefficient of cos θ. Thus, this conic section is a parabola since its eccentricity is 1.

The value of the directrix is determined as;

d = k/e = 3/1 = 3

The denominator of the polar equation of this conic section contains (-cos θ) which implies that this parabola opens towards the right and thus the equation of its directrix is;

x = -3

Thus, the polar equation represents a parabola that opens towards the right with a directrix located at x = -3. Choice D fits this criteria

You might be interested in

(10 POINTS + BRAINLIEST AND THANKS

kirill115 [55]

1. Since it's increased by 40% it would be 140%
2. It would be $294

7 0

3 years ago

Read 2 more answers

4(5x-9)=20x-45 i have no idea how to solve this

Marat540 [252]

Answer: no solution

Step-by-step explanation:

20x - 36 = 20x - 45

-20x. -20x

-36 = -45 since this is not true, the answer is there is no solution

4 0

3 years ago

A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet

gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

$h(x)=10+0.1(x^{1.5})$

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

$h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}$

$s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx$

$s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx$

Let $1+0.0225x=t$

$dx=\frac{1}{0.0225}dt$

$s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt$

$s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}$

$s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}$

$s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)$

s=28.21

Weight of cable= $28.21\times 10.4=293.38$ pound

8 0

3 years ago

Please help it due ASAP <br> Pls SHOW WORKINGS also.

marusya05 [52]

Answer:

Step-by-step explanation:

Angle 5 is equal to angle 8 because the two angles are an alternate interior angle. We already know that angle 7 and 8 are supplementary because it's adjacent to each other on a straight line. So, since angle 5 and 8 is equal to each other, angle 5 is also supplementary to angle 7.

4 0

3 years ago

Not sure how difficult this would be to solve

mr_godi [17]

F (x) = x^2 - 2x + 1
f (x) = (-2)^2 - 2(-2) + 1
= 4 + 4 + 1
= 9
f (x) = ( 0 )^2 - 2 (0) + 1
= 0 - 0 + 1
= 1
0 = x^2 - 2x + 1
x^2 = 2x - 1 = 1
f (2) = 2^2 - 2(2) + 1
= 4 - 4 + 1
= 1
f (3) = 3^2 - 2(3) + 1
= 9 - 6 + 1
= 3 + 1
= 4

3 0

2 years ago