Answer:
![69.7 -2.58 \frac{2.8}{\sqrt{772}}=69.44](https://tex.z-dn.net/?f=%2069.7%20-2.58%20%5Cfrac%7B2.8%7D%7B%5Csqrt%7B772%7D%7D%3D69.44)
![69.7 +2.58 \frac{2.8}{\sqrt{772}}=69.96](https://tex.z-dn.net/?f=%2069.7%20%2B2.58%20%5Cfrac%7B2.8%7D%7B%5Csqrt%7B772%7D%7D%3D69.96)
And we can conclude that the true mean for the heights of mens between the ages of 18 to 24 is between 69.44 and 69.7 inches.
Step-by-step explanation:
For this case we have the following sample size n =772 from men recruits between the ages of 18 to 24
represent the sample mean for the heigth
represent the population standard deviation
We want to construct a confidence interval for the true mean and we can use the following formula:
![\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Cbar%20X%20%5Cpm%20z_%7B%5Calpha%2F2%7D%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
The confidence level is 0.99 or 99%o then the significance level is
and
and if we find for a critical value in the normal tandar ddistirbution who accumulates 0.005 of the area on each tail we got:
![z_{\alpha/2}= 2.58](https://tex.z-dn.net/?f=z_%7B%5Calpha%2F2%7D%3D%202.58)
And replacing we got:
![69.7 -2.58 \frac{2.8}{\sqrt{772}}=69.44](https://tex.z-dn.net/?f=%2069.7%20-2.58%20%5Cfrac%7B2.8%7D%7B%5Csqrt%7B772%7D%7D%3D69.44)
![69.7 +2.58 \frac{2.8}{\sqrt{772}}=69.96](https://tex.z-dn.net/?f=%2069.7%20%2B2.58%20%5Cfrac%7B2.8%7D%7B%5Csqrt%7B772%7D%7D%3D69.96)
And we can conclude that the true mean for the heights of mens between the ages of 18 to 24 is between 69.44 and 69.7 inches.
Answer: X=2, PR=40
Step-by-step explanation:
given that the two triangles are equal/congruent
------------------------
solve for x
10x+5=25
10x=20
x=2
--------------------
solve for y
33=7y-2
35=7y
y=5
------------------
solve for PR
PR=8y
PR=8(5)
PR=40
Hope this helps!! :)
Answer: 35
Just took a test on this