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3 years ago

The product The product of 5 and a number n is at least -25

Mathematics

2 answers:

kogti [31]3 years ago

5 0

the answer is n > -5

Sophie [7]3 years ago

4 0

Answer:

$n > - 5$

Step-by-step explanation:

$5 \times n > - 25 \\ n > - 25 \div 5 \\ n > - 5$

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Which description best fits the graph

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Decreasing then increasing, y goes down then y goes back up

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3 years ago

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In an 80/20 mortgage, what is the second mortgage used for?

avanturin [10]

Answer:

The first loan covers 80 percent of the home’s price, while the second covers the remaining 20 percent.

Step-by-step explanation:

they are still a home price percentage

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3 years ago

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If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. see if those v

kkurt [141]

a=4 , b=3 These values make the equation true .

Step-by-step explanation:

Here we have , If a and b are both integers and b does not equal 0, then -(a/b) = (-a)/b = a/(-b) Choose two values for a and b. We need to find if those values make the equation true . Let's find out:

We have the following equation:

-(a/b) = (-a)/b = a/(-b) , Let a=4 , b=3 , So

⇒ $-(a/b) = (-a)/b = a/(-b)$

⇒ $-\frac{a}{b} = \frac{-a}{b} = \frac{a}{-b}$

⇒ $-\frac{4}{3} = \frac{-4}{3} = \frac{4}{-3}$

⇒ $-\frac{4(-1)}{3} = \frac{-4(-1)}{3} = \frac{4(-1)}{-3}$ { Multiplying by -1 }

⇒ $\frac{4}{3} = \frac{4}{3} = \frac{4}{3}$

Therefore , These values make the equation true .

7 0

3 years ago

7^3 times 7^-7 times 7

dusya [7]

Hello there! :)

Answer: $\frac{1}{343}$

*The answer must have a fraction.*

Step-by-step explanation:

Lesson: Zero and Negative Exponents.

Distributive property: a(b+c)=ab+ac

First, you apply exponent rule.

$a^b*a^c=a^b^+^c$

$7^-^3$

$\frac{1}{7^3}=7^3=7*7*7=343$

Final answer: $\frac{1}{343}$

Hope this helps!

Thanks!

-Charlie

Have a great day!

4 0

2 years ago

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample. To determine

zimovet [89]

Answer:

(a) 0.2650

(b) 0.0111

(d) 0.0006

Step-by-step explanation:

Given that:

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample.

Suppose that the number of CFUs that appear after incubation follows a Poisson distribution with mean μ = 15. &;

If the area of the agar plate is 75cm²;

what is the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate.

We can determine the mean number of CFUs that appear on a 25cm² area of the plate as follows;

75cm²/25cm² = 3

Since;

mean μ = 15

mean number of CFUs that appear on a 25cm² = 15/3 = 5 CFUs

Thus ; the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate is estimated as:

= P(X < 4)

Using the EXCEL FUNCTION ( = poisson.dist(3, 5, TRUE) )

we have ;

P(X < 4) = 0.2650

b) If you were to count the total number of CFUs in 5 plates, what is the probability you would observe more than 95 CFUs?

Given that the total number of CFUs = 5 plates; then the mean number of CFUs in 5 plates = 15×5 = 75 CFUs

The probability is therefore = P( X > 95 )

= 1 - P(X ≤ 95)

= 1 - poisson.dist(95,75,TRUE) ( by using the excel function)

= 0.0111

c) Repeat the probability calculation in part (b) but now use the normal approximation.

Let assume that the mean and the variance of the poisson distribution are equal

Then;

$X \sim N (\mu = 75 , \sigma^2 = 75)$

We are to repeated the probability calculation in part (b) from above;

So:

P( X > 95 )

use the normal approximation

From standard normal variable table:

P(Z > 2.3094)

Using normal table

P(Z > 2.3094) = 0.0105

(d) Find the difference between this value and your answer in part (b).

So;

the difference between the value in part c and part b is;

= 0.0111 - 0.0105

$= 6*10^{-4}$

= 0.0006 to four decimal places

5 0

3 years ago