Esmeralda has decided that every month, for as long as she can

A recipe for 1 batch of cookies calls for 1/2 of a cup of raisins. Diego has 2 cups of raisins. How many batches can he make?

Simora [160]

$\begin{array}{ccll} batches&cups\\ \cline{1-2} 1&\frac{1}{2}\\[1em] x&2 \end{array}\implies \cfrac{1}{x}=\cfrac{~~\frac{1}{2} ~~}{2}\implies \cfrac{1}{x}=\cfrac{~~\frac{1}{2} ~~}{\frac{2}{1}}\implies \cfrac{1}{x}=\cfrac{1}{2}\cdot \cfrac{1}{2} \\\\\\ \cfrac{1}{x}=\cfrac{1}{4}\implies 4=x$

8 0

3 years ago

How many Line segment in square, rectangle and circles

nlexa [21]

Answer:

You need four of them in order to construct a square. and rectangle.A circle doesn't have line segments. It is a curve, not made up of straight lines.

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Can y’all help me I got this wrong help ASAP

Maksim231197 [3]

It should be A, D & E im pretty sure.

6 0

3 years ago

Expand and simplify 2(5x - 1) - (2x - 5)

muminat

2(5x-1)-(2x-5).

=10x-2-2x+5.

=10x-2x+5-2.

=8x+3.

Hope it helps.

7 0

3 years ago

I need help please, I am so confused.

vazorg [7]

Answer:

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

Step-by-step explanation:

x-intercepts are when the curve intercepts the x-axis, so when y =0.

Therefore, to find the x-intercepts, substitute y = 0 and solve for x.

The vertex is the turning point: the minimum point of a parabola that opens upward, and the maximum point of the parabola that opens downward. As a parabola is symmetrical, the x-coordinate of the vertex is the midpoint of the x-intercepts.

Equation: $y=x(x-2)$

$\implies x(x-2)=0$

$\implies x=0$

$\implies (x-2)=0 \implies x=2$

Therefore, the x-intercepts are x = 0 and x = 2

The midpoint of the x-intercepts is x = 1, so the x-coordinate of the vertex is x = 1

Equation: $y=(x-4)(x+5)$

$\implies (x-4)(x+5)=0$

$\implies (x-4)=0 \implies x=4$

$\implies (x+5)=0 \implies x=-5$

Therefore, the x-intercepts are x = -5 and x = 4

The midpoint of the x-intercepts is x = -0.5, so the x-coordinate of the vertex is x = -0.5

Equation: $y=-5x(3-x)$

$\implies -5x(3-x)=0$

$\implies -5x=0 \implies x=0$

$\implies (3-x)=0 \implies x=3$

Therefore, the x-intercepts are x = 0 and x = 3

The midpoint of the x-intercepts is x = 1.5, so the x-coordinate of the vertex is x = 1.5

$\begin{tabular}{| c | c | c |}\cline{1-3} Equation & x-intercepts & x-coordinate of vertex\\\cline{1-3} $y=x(x-2)$ & $x=0, x=2$ & $x=1$\\\cline{1-3} $y=(x-4)(x+5)$ & $x=-5, x=4$ & $x=-0.5$\\\cline{1-3} $y=-5x(x-3)$ & $x=0, x=3$ & $x=1.5$\\\cline{1-3} \end{tabular}$

4 0

2 years ago