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Keith_Richards [23]
3 years ago
5

True or false 1. All parallelograms are squares.2. All squares are parallelograms. 3. All trapezoids are scalene.4. All squares

are rhombuses. 5. All rhombuses are squares.6. All rectangles are squares. 7. All squares are rectangles.
Mathematics
1 answer:
ruslelena [56]3 years ago
4 0
1-2:<span>Yes. But not all parallelograms are squares</span><span>
3-false ! are </span><span>plane figures.
4-True ! </span>Every square is a rhombus<span>
5-False , </span><span>every rhombus is not a square.
6-7 : </span>Yes, all Squares are rectangles, but not all rectangles are squares because it needs to have all equal sides.
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In an arithmetic sequence the sum of the first six odd-numbered terms (a1,a3,a5,a7,a9 and a11) is 60. find the sum of the first
alexandr1967 [171]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
ZA and ZB are vertical angles. If mZA= (5x – 4) and mZB = (2x – 1)º, then find the value of x. INI​
natulia [17]

Answer:

x = 1

Step-by-step explanation:

It is given that,

∠A and ∠B are vertical angles.

∠A = (5x – 4) and ∠B = (2x – 1)

We need to find the value of x.

We know that, the vertical angles are equal. So,

∠A=∠B

(5x – 4)=(2x – 1)

Taking like terms together,

5x-2x = 4-1

3x=3

x = 1

So, the value of x is equal to 1.

4 0
3 years ago
The question is: find 55% of $4.80...how do I find the answer?
tresset_1 [31]
4.80 = 100%
   x   = 55%

Cross Multiply

100 * x = 55 * 4.80
100x = 264
x = <u>264</u>
      100
x = 2.64

Solution: $2.64
6 0
3 years ago
Read 2 more answers
If there are 31,536,000 seconds in one year how many seconds are in a millennium
Naily [24]

A millennium is 1000 years.

Multiply the number of seconds in 1 year by 1000:

31,536,000 x 1,000 = 31,536,000,000 seconds.

5 0
3 years ago
Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i
aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175

Positive when there is raritanium:

98% of 13%

P(A) = 0.98*0.13 = 0.1274

What is the probability the rock sample actually contains raritanium?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967

0.967 = 96.7% probability the rock sample actually contains raritanium

7 0
2 years ago
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