All categories

2 years ago

TIMER !! HELP!!

Mathematics

1 answer:

Anvisha [2.4K]2 years ago

8 0

Answer:

Step-by-step explanation:

The vertex of a parabola lies on the axis of symmetry.

You might be interested in

HELP MEEEEEEEEEEEEEEEEEEEEE PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

kap26 [50]

Part a

Setting $x=6$ , $y=7.9(1.02)^6 \approx \boxed{8.9}$

Part b

Setting $x=14$ , $y=7.9(1.02)^{14} \approx \boxed{10.4}$

7 0

1 year ago

If 7 || m, find the value of x (9x - 4)' Us 4+ (5x + 16)"

KonstantinChe [14]

Answer:

Step-by-step explanation:

9x - 4 + 5x + 16 = 180

14x + 12 = 180

14x = 168

x = 12

7 0

3 years ago

Read 2 more answers

A movie was 3 1/2 hours long if Lilly turned of the movie off 1/4 of the way through how much time did she spend watching

Nuetrik [128]

Answer:

7/8 of an hour

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Complete the point-slope equation of the line through

jek_recluse [69]

Answer:

y +1 = 3/4(x -1)

Step-by-step explanation:

8 0

2 years ago

The n term of a geometric sequence is denoted by Tn and the sum of the first n terms is denoted by Sn.Given T6-T4=5/2 and S5-S3=

Leno4ka [110]

1 step: $S_{5}=T_{1}+T_{2}+T_{3}+T_{4}+T_{5}$ , $S_{3}=T_{1}+T_{2}+T_{3}$ , then
$S_{5}-S_{3}=T_{4}+T_{5}=5$ .

2 step: $T_{n}=T_{1}*q^{n-1}$ , then
$T_{6}=T_{1}*q^{5}$
$T_{5}=T_{1}*q^{4}$
$T_{4}=T_{1}*q^{3}$
$T_{3}=T_{1}*q^{2}$
and $\left \{ {{T_{6}-T_{4}= \frac{5}{2} } \atop {T_{5}+T_{4}=5}} \right.$ will have form $\left \{ {{T_1*q^{5}-T_{1}*q^{3}= \frac{5}{2} } \atop {T_{1}*q^{4}+T_{1}*q^{3}=5} \right.$ .

3 step: Solve this system $\left \{ {{T_1*q^{3}*(q^{2}-1)= \frac{5}{2} } \atop {T_{1}*q^{3}*(q+1)=5} \right.$ and dividing first equation on second we obtain $\frac{q^{2}-1}{q+1}= \frac{ \frac{5}{2} }{5}$ . So, $\frac{(q-1)(q+1)}{q+1} = \frac{1}{2}$ and $q-1= \frac{1}{2}$ , $q= \frac{3}{2}$ - the common ratio.

4 step: Insert $q= \frac{3}{2}$ into equation $T_{1}*q^{3}*(q+1)=5$ and obtain $T_{1}* \frac{27}{8}*( \frac{3}{2}+1 ) =5$ , from where $T_{1}= \frac{16}{27}$ .

5 0

3 years ago