What is the solution to this equation?
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The equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3
The line is passing through the point = (-6,-3)
The slope of the line = 0
The point slope form is
Substitute the values in the equation
(y-(-3)) = 0×(x-(-6))
We have to convert this equation the slope intercept form
Slope intercept form is
y = mx + b
Where m is the slope of the line
b is the y intercept
(y-(-3)) = 0×(x-(-6))
y+3 = 0×(x+6)
y+3 = 0
y = -3
Hence, the equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3.
Learn more about slope intercept form here
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I found the corresponding image. Pls. see attachment.
<span>The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).
A rotation translation must be used to make the two polygons coincide.
A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D </span>
<span>The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).
A rotation translation must be used to make the two polygons coincide.
A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D </span>